From.the calculated area and perimeter of the field, it will cost the farmer $475740 to fence and seed the pasture.
<h3>What is the area of the field?</h3>
The area of the field is calculated as follows:
Area of square = 450 ft × 450 ft = 202500 square feet
Area of triangle = (450 ft × 120 ft)/2 = 27000 square feet
Area of field = 229500 square feet
Cost of seeding the field = 229500 × $2 = $459000
Perimeter of the field = 450 + 450 + 450 + 255 + 255 = 1860 ft
1 ft = 1/3 yard
1860 ft = 1860 × 1/3 yards = 620 yards
Cost of fencing = 620 × $27 = $16740
Total cost of seeding and fencing = $475200
Therefore, it will cost the farmer $475740 to fence and seed the pasture.
Learn more about area and perimeter at: brainly.com/question/19819849
The solution to given system of equations are (x, y) = (4, 2)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 14 ---------- eqn 1
3x - 4y = 4 --------- eqn 2
We have to solve the given system of equations
We can solve the above system of equations by elimination method
<em><u>Multiply eqn 1 by 3</u></em>
3(2x + 3y = 14)
6x + 9y = 42 --------- eqn 3
<em><u>Multiply eqn 2 by 2</u></em>
2(3x - 4y = 4)
6x - 8y = 8 ----------- eqn 4
<em><u>Subtract eqn 4 from eqn 3</u></em>
6x + 9y = 42
6x - 8y = 8
( - ) --------------
9y + 8y = 42 - 8
17y = 34
<h3>y = 2</h3>
<em><u>Substitute y = 2 in eqn 1</u></em>
2x + 3(2) = 14
2x + 6 = 14
2x = 14 - 6
2x = 8
<h3>x = 4</h3>
Thus the solution to given system of equations are (x, y) = (4, 2)
Answer:
x^5y^5
Step-by-step explanation:
<em>here's</em><em> your</em><em> solution</em>
=> if base are same then power get added in multiplication
=> so, x^2 * y^4 * x^3 * y^1
=> x^2 * x^3 * y^4 * y^1
=> x^5*y^5
hope it helps
Answer:
The answer to this question would be B:
Based on the question, since the weight of the weight plates are 20 lbs, this would be represented by the 20x in the function. As well, the 5 lb barbell would be represented by the 5 in the function. The range of the function is determined by the amount of weight plates are added. So if I added one weight plate the equation would equal, f(x) = 20(1) + 5 = 25. This continues on the more and more weight plates you add.
Hope this reached you well :)
Step-by-step explanation:
20 = weight of the weight plates
x = amount of weight plates.
5 = weight of the barbell
f(x) = 20(0) + 5 = 5
f(x) = 20(1) + 5 = 25
f(x) = 20(2) + 5 = 45
f(x) = 20(3) + 5 = 65
f(x) = 20(4) + 5 = 85
