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Anna35 [415]
2 years ago
10

Solve, solve , solve

Mathematics
1 answer:
Wittaler [7]2 years ago
5 0

Answer:

1.) 5 1/4

2.)1 1/2

Step-by-step explanation:

umm.....

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What percent is students walk home from school
AveGali [126]

Answer:

50percent

Step-by-step explanation:

5 0
3 years ago
CAN SOMEONE PLEASE PLEASE PLEASE HELP ME, YOU’LL GET FREE EASY POINTS IF YOU GIVE ME THE RIGHT ANSWER !!
bekas [8.4K]

Answer:

  1. reflection across BC
  2. the image of a vertex will coincide with its corresponding vertex
  3. SSS: AB≅GB, AC≅GC, BC≅BC.

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

__

<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

  • side AB and side GB
  • side AC and side GC
  • angle ABC and angle GBC
  • angle BAC and angle BGC

And the reflexive property of congruence tells us BC corresponds to itself:

  • side BC and side BC

There are four available congruence theorems applicable to triangles that are not right triangles

  • SSS -- three pairs of corresponding sides
  • SAS -- two corresponding sides and the angle between
  • ASA -- two corresponding angles and the side between
  • AAS -- two corresponding angles and the side not between

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

3 0
2 years ago
Read 2 more answers
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
PLEASE HELP!! Calculate the slope of the line passing through the following two points: write your slope as a reduced improper f
Alekssandra [29.7K]

Answer:

1

Step-by-step explanation:

slope formula:

\frac{y_2-y_1}{x_2-x_1}\\\\=\frac{3-(-18)}{2-(-19)}\\=\frac{21}{21}=1

6 0
3 years ago
Read 2 more answers
The water level in a tank can be modeled by the function h(t)=8cos(pi t /7)+11.5, where t is the number of
denis23 [38]

Answer:

NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height

Step-by-step explanation:

Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero

Velocity is the change in distance with respect to time.

V = {d(h(t)}/dt = -8π/7sin(πt/7)

At maximum height, -8π/7sin(πt/7) = 0

-Sin(πt/7) = 0

sin(πt/7) = 0

Taking the arcsin of both sides

arcsin(sin(πt/7)) = arcsin0

πt/7 = 0

t = 0

This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height

4 0
3 years ago
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