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2 years ago

Solve, solve , solve

Mathematics

1 answer:

Wittaler [7]2 years ago

5 0

Answer:

1.) 5 1/4

2.)1 1/2

Step-by-step explanation:

umm.....

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I need help on this???

Aliun [14]

Use the geometric mean for right triangles here. Like this $\frac{9}{y}= \frac{y}{7}$ . Cross multiply to get $y^{2}=63$ , and $y= \sqrt{63}$ . That simplifies down to $y= \sqrt{9*7}$ . Pull out the 9 as a perfect square of 3 and you're left with $y=3 \sqrt{7}$ , first choice above.

4 0

3 years ago

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Fine -x when x = -17

Rashid [163]

Answer:

Step-by-step explanation:

-(-17)= 17

3 0

3 years ago

Please pick one of the options.

olchik [2.2K]

9880 different possibilities are there in Sally's new combination option second 9880 is correct.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

Total unique numbers consists in a Sally locker = 3

From the digits 0 to 39

Total numbers = 40

Apply combination formula:

= C(40, 3)

= 40!/(3!37!)

= 9880

Thus, 9880 different possibilities are there in Sally's new combination option second 9880 is correct.

Learn more about permutation and combination here:

brainly.com/question/2295036

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6 0

2 years ago

Complete the missing parts of the paragraph proof.

mariarad [96]

THANK YOU FOR YOUR HELP.

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3 years ago

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What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago