the new radius be to meet the client's need is 4.9 cm .
<u>Step-by-step explanation:</u>
Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:
Let we have two cylinders of volume
with parameters as follows :

We know that volume of cylinder is
, According to question volume of both cylinder is equal i.e
⇒ 
⇒ 
⇒ 
⇒ 
⇒
Putting all values
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the new radius be to meet the client's need is 4.9 cm .
Answer:
11
Step-by-step explanation:
Given:
3/2y - 3 + 5/3z
When
y=6
z=3
3/2y - 3 + 5/3z
Substitute the value of y and z
3/2(6) - 3 + 5/3(3)
=18/2 - 3 + 15/3
=9-3+5
=6+5
=11
C. line 4 is the first one
C. -15 for the second part
Answer:
(A) 0.15625
(B) 0.1875
(C) Can't be computed
Step-by-step explanation:
We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let X = Amount of time taken by student to complete a statistics quiz
So, X ~ U(32 , 64)
The PDF of uniform distribution is given by;
f(X) =
, a < X < b where a = 32 and b = 64
The CDF of Uniform distribution is P(X <= x) =
(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 -
= 1 -
=
= 0.15625
(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) =
=
= 0.34375
P(X < 37) =
=
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) Probability that student complete the quiz in exactly 44.74 minutes
= P(X = 44.74)
The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.