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2 years ago

Number with the digit 8 in the tens place

2 answers:

5 0

Tens place is to the left of the decimal (whereas tenths would be to the right).

4616484

182

1546286.12354

85236987.4

80

ratelena [41]2 years ago

5 0

1) 98
2) 108
3) 518
4) 68
5) 238
6) 348
7) 18
8) 28
9) 368
10) 978

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Grace is an hourly employee, and the line that models her total pay in dollars

tresset_1 [31]

Answer: Hello mate!

if x is the amount of hours worked, 45 is the slope and the y intercept is 35.

A linear equation has the form of y = ax + b, where a is the slope and b is the y-intercept, then the equation that we have is:

y = 45*x + 35

this means that she wins $45 per hour, and has a plane amount of $35, indiferent of the amount of hours worked.

Then the correct answer is

C) Grace's wage is $45 an hour, and it appears that she received a signing bonus of $35.

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2 years ago

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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago

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D,A,B,C i think this is correct !

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2 years ago

Ashton answer this what is 8x8

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Answer:

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Answer:

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