Point slope form is y-(-4) = 1/2(x-(-2)
y+4 =1/2 (x+2)
now the standard form 2y+8=x+2
so -x+2y=-6 is the equation for line p in standard form
Answer:
Below
Step-by-step explanation:
First I found the area of the portion that extends off (if that makes sense??)
It is a triangle, so use A = bh/2
A = (2)(6) / 2
= 6 cm^2
Next I found the area of the rectangle using A = LW
A = (6)(3)
= 18 cm^2
Total area = 18 + 6
= 24 cm^2
Hope this helps! Best of luck <3
Answer: D. 170
Step-by-step explanation:
From the identity:
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)
Answer: b. g(x)=cos^-1(1/x)
The slope of the line given its equation is calculated through, m = -A / B. The slope of the given line is 4/3. The line perpendicular to it has the slope of -3/4. The slope-point form of the equation is,
y - y1 = m(x - x1)
where m is the slope and x1 and y1 the abscissa and ordinate of the point, respectively.
Substituting the values above,
y --2 = (-3/4)(x - 3)
Simplifying the equation gives 3x + 4y = 1.
