A) yes
B) yes
C) no
For each of these, substitute the value of x in the ordered pair into x in the function.
For A, x = -5; -5<2, so the piece of the function we want is f(x) = 3. In our ordered pair, y=f(x)=3, so yes, it is a solution.
For B, x = 2; 2≤2<6, so the piece of the function we want is f(x) = -x+1. In our ordered pair, y=f(x)=-1; -2+1=-1, so yes, it is a solution.
For C, x = 8; 8≥6, so the piece of the function we want is f(x) = x. In our ordered pair, y=f(x)=-7; -7≠8, so no, it is not a solution.
The 4 functions are:




Let's keep in mind that for large values of x, a quadratic function grows faster than a linear function:

for large values of x
In this problem, we can see that the only quadratic function is

, while all the others are linear functions, so the function that grows faster for large values of x is
4 in (4,-5) implies positive x-axis.
-5 in (4,-5) implies negative y-axis.
Since x is positive and y is negative in fourth quadrant, so the answer is
QUADRANT IV (or 4th quadrant.
The answer is ....................
X=5
Y=3
Answer:
See explanation.
Step-by-step explanation:
Part C)

When adding a positive to a negative, the result will be the sign of the larger absolute value. In this case, 10 is greater than 5, so the result will be negative.
Adding a negative is also the same thing as subtracting a positive.

For your second problem, 5 is larger than 3, so the result will be positive.

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When adding a positive to another positive, the result will be positive.

When adding a number to zero, the answer will always be the number.

Part D)
When multiplying a positive times a negative, the result will always be negative.


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When multiplying a positive times a positive, the result will always be positive.

When multiplying a positive or a negative times zero, the result will always be zero.
