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Fittoniya [83]
3 years ago
11

40 POINTS Can someone please answer question 8 and 9 for me please

Physics
2 answers:
fgiga [73]3 years ago
8 0

⚘<em>R</em><em>e</em><em>f</em><em>e</em><em>r</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>a</em><em>t</em><em>t</em><em>a</em><em>c</em><em>h</em><em>m</em><em>e</em><em>n</em><em>t</em><em>!</em><em>!</em><em>~</em><em> </em>:)

  • <u>S</u><u>o</u><u>r</u><u>r</u><u>y</u><u> </u><u>b</u><u>u</u><u>t</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>9</u><u>t</u><u>h</u><u> </u><u>i</u><u>s</u><u> </u><u>o</u><u>u</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>m</u><u>y</u><u> </u><u>e</u><u>x</u><u>p</u><u>e</u><u>r</u><u>t</u><u>i</u><u>s</u><u>e</u>

Artist 52 [7]3 years ago
5 0

Answer:

for 8th one it is 33.4k joules and for ninth one i think 95degree C.

Explanation:

hope this helps

thank you.

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On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects. At Earth's surface the acceleration of gravity is about 9.8 metres (32 feet) per second per second.

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an egg (0.05 kg) hits the ground at a speed of 10 m/s and cracks . what was the momentum of the egg when it hit?
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What grade of sprain is a completely torn ligament?
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Read 2 more answers
A concave lens has a focal length of 25cm. it's power in diaptor is​
IgorLugansk [536]

As we know that :

\begin{gathered}\large{\boxed{\sf{P \: = \: \dfrac{1}{f}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{1}{-25}}}\end{gathered}

Power, is in Meter. So divide focal length by 100

\begin{gathered}\rightarrow {\sf{P \: = \: \dfrac{1}{\dfrac{-25}{100}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{-100}{25}}} \\ \\ \rightarrow {\sf{P \: = \:- 4}} \\ \\ \underline{\sf{\therefore \: Power \: of \: Concave \: lens \: is \: - \: 4D}}\end{gathered}

8 0
2 years ago
A thin stream of water flows smoothly from a faucet and falls straight down. At one point the water is flowing at a speed of v1
MrRa [10]

Answer:

The vertical distance between these two points is 12.28 cm.

Explanation:

Given that,

Speed of water = 1.23 m/s

Diameter at lower point d'= 0.787 d

We need to calculate the speed of water

Using continuity equation

A_{1}v_{1}=A_{2}v_{2}

\dfrac{\pi\times d^2}{4}v_{1}=\dfrac{\pi\times d'^2}{4}v_{2}

v_{2}=v_{1}\times(\dfrac{d}{d'})^2

Put the value into the formula

v_{2}=1.23\times(\dfrac{d}{0.787d})^2

v_{2}=1.98\ m/s

We need to calculate the  vertical distance h between these two points

Using Bernoulli theorem

P_{1}+\dfrac{1}{2}\rho v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho v_{2}^2+\rho gh_{2}

Here, P₁ = P₂ = atmosphere pressure is same because both end is open

\dfrac{1}{2}\rho(v_{2}^2-v_{1}^2)=\rho\times g(h_{1}-h_{2})

(v_{2}^2-v_{1}^2)=2g(h_{1}-h_{2})

2g\times\Delta h=(v_{2}^2-v_{1}^2)

\Delta h=\dfrac{1.98^2-1.23^2}{2\times9.8}

\Delta h=12.28\ cm

Hence, The vertical distance between these two points is 12.28 cm.

6 0
4 years ago
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