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Travka [436]
3 years ago
11

A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?

Physics
2 answers:
timurjin [86]3 years ago
7 0

The speed of the ball after 4s is 10 m/s.

There's not enough information to find its velocity. (We would need to know what direction it's moving.)

erica [24]3 years ago
4 0

Explanation:

Given:

v₀ = 0 m/s

a = 2.50 m/s²

t = 4 s

Find: v

v = at + v₀

v = (2.50 m/s²) (4 s) + 0 m/s

v = 10 m/s

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Which letter represents the wavelength of the wave?
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The greek letter λ (lamda) is used to represent the wavelength of the wave.
6 0
3 years ago
Three noise sources produce volume (loudness) levels of 70, 73, and 80 dB when acting separately. When the sources act together,
Mashutka [201]

Sound at 70 dB is 70 dB louder than the human reference level.  That's 10⁷ times as much as the reference sound power.

Sound at 73 dB is 73 dB louder than the human reference level.  That's 10⁷.³  or  2 x 10⁷  times as much as the reference sound power.

Sound at 80 dB is 80 dB louder than the human reference level.  That's 10⁸  or 10 x 10⁷ times as much as the reference sound power.

Now we can adumup:

Intensity of all 3 sources = (10⁷) + (2 x 10⁷) + (10 x 10⁷)

Intensity = (13 x 10⁷) times the sound power reference intensity.

Intensity in dB = 10 log (13 x 10⁷) = 10 (7 + log(13)

Intensity = 70 + 10 log(13)

Intensity = 70 + 10 (1.114)

Intensity = 70 + 11.14

Intensity = <em>81.14 dB</em>

<em>______________________________________</em>

Looking at the questioner's profile, I seriously wonder whether I'll ever get a comment in return from this creature, and how I'll ever find out if my solution is correct.  For that matter, I'm also seriously questioning how and whether my solution will ever be used for anything.

8 0
3 years ago
The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal re
inna [77]

Answer:

Explanation:

The thermal efficiency of a Power cycle \eta = \dfrac{Q_H -Q_c}{Q_H}

where;

\eta = 50\% = 0.5

Q_H = Heat \ flow \ from \ higher \ temperature

Q_c = Heat \ flow \ from \ lower \ temperature

0.5 = \dfrac{Q_H -Q_c}{Q_H}

0.5 Q_H = Q_H - Q_c --- (1)

Q_c = 0.5 Q_H         ---- (2)

The coefficient of performance is:

COP_R = \dfrac{Q_c}{Q_H -Q_c}

let replace the value of Q_c = 0.5 Q_H   in the above equation then;

COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}

COP_R = \dfrac{0.5Q_H}{0.5 Q_H}

COP_R = 1

The

On the other hand,  the heat pump

COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}

By replacing equation (1) into the above equation; we have:

COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}

COP_{HP} = \dfrac{1}{0.5}

COP_{HP} =2

t

5 0
3 years ago
||||| A ball on a porch rolls 60 cm to the porch’s edge, drops 40 cm, continues rolling on the grass, and eventually stops 80 cm
3241004551 [841]

Answer:

d = 145.6 cm

Explanation:

first ball rolls on the porch by total distance

x_1 = 60 cm

Then again it will move on horizontal floor

x_2 = 80 cm

also in vertical direction it will drop down

y = 40 cm

so we have

x = 60 + 80

x = 140 cm

y = 40 cm

so magnitude of net displacement of the ball is given as

d = \sqrt{140^2 + 40^2}

d = 145.6 cm

8 0
3 years ago
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