Answer:
u = 3.35 m/s
Explanation:
given,
mass , m = 0.455 kg
R = 0.675 m
Height of Loop = 1.021 m
the speed required at the top of loop be v
equating the force vertically
v² = 6.622
v = 2.57 m/s
Let the initial speed of ball be u
using conservation of energy
where, 
0.7 u² = 7.85092
u² = 11.2156
u = 3.35 m/s
the initial speed is 3.35 m/s
Answer: 40
Explanation:
= 34 + 5 * 1.2465
= 40.2325
= 40
The number of significant figures in the answer should be the same as the number with the least number of significant figures that any of the digits in the equation have.
32 has 2 significant figures so the answer has to be 2 significant figures which is 40.
Answer c, velocity would be the answer.
When you first pull back on the pendulum, and when you pull it back really high the Potential Energy is high and the Kinetic Energy is low, But when up let go, and it gets right around the middle, that's when the Potential energy transfers to Kinetic, at that point the kinetic Energy is high and the potential Energy is low. But when it comes back up at the end. The same thing will happen, the Potential Energy is high, and the Kinetic Energy is low. Through all of that the Mechanical Energy stays the same.
I hope this helps. :)
Brainliest?
Answer:
The helicopter uses 35 gallons to fly for 5 hours.
Explanation:
The amount of gas that a helicopter uses for flying varies directly proportional to the number of hours spent flying.
g ∝ T
where g represents amount of gas and T time of flight.
Then,
The helicopter files 4 hours and uses 28 gallons of fuel.
Here, g₁= 28 gallons, T₁=4 hours
g₂=?, T₂=5 hours.
⇒28×5= g₂×4
⇒ g₂×4=28×5
gallons
The helicopter uses 35 gallons to fly for 5 hours.
