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2 years ago

A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?

Physics

2 answers:

timurjin [86]2 years ago

7 0

The speed of the ball after 4s is 10 m/s.

There's not enough information to find its velocity. (We would need to know what direction it's moving.)

erica [24]2 years ago

4 0

Explanation:

Given:

v₀ = 0 m/s

a = 2.50 m/s²

t = 4 s

Find: v

v = at + v₀

v = (2.50 m/s²) (4 s) + 0 m/s

v = 10 m/s

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3 years ago

A spherical raindrop 2.5 mm in diameter falls through a vertical distance of 3900 m. Take the cross-sectional area of a raindrop

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Answer:

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Explanation:

t = Time taken

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3 years ago

(Double points) A machine receives electricity that enables it to deliver a total of 8,542 N of force for the completion of its

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3 years ago

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3 years ago

A ball is pushed into a spring-loaded launcher with a force of 20 N, which compresses the spring 0.08 m.

damaskus [11]

Answer:

0.8J

Explanation:

Given parameters:

Force = 20N

Compression = 0.08m

Unknown:

Spring constant = ?

Elastic potential energy = ?

Solution:

To solve this problem, we use the expression below:

F = k e

F is the force

k is the spring constant

e is the compression

20 = k x 0.08

k = 250N/m

Elastic potential energy;

EPE = $\frac{1}{2}$ k e² = $\frac{1}{2}$ x 250 x 0.08²

Elastic potential energy = 0.8J

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2 years ago