I think that the correct answer is 33
Answer:
vertical asymptotes at x=0
no horizontal asymtotes
Step-by-step explanation:
https://simplisico.com/share/q/OPlkHJgPrpb7WW56eMHXWLbG
The ellipse will be inscribed in the rectangle.
Because the rectangle measures 8 mi by 6 mi, the ellipse has
a = 8/2 = 4 mi (major axis)
b = 6/2 = 3 mi (minor axis)
The equation for the ellipse is
x^2/a^2 + y^2/b^2 = 1
That is
x^2/4^2 + y^2/3^2 = 1
x^2/16 + y^2/9 = 1
Answer:
x^2/16 + y^2/9 = 1
Answer:
2x² + x - 1 = 0
a= 2 b= 1 c= -1
x = [ -b +- sqr rt( b^2 -4ac) ] / 2*a
x = -1 +- sqr rt (1 - 4 *2*-1) / 4
x1 = [ -1 + (sqr rt (1 +8)) / 4
x1 = ( -1 + sqr rt (9)) / 4
x1 = (-1 + 3) / 4
x1 = .5
x2 = (-1 -3) / 4
x2 = -4 / 4
x2 = -1
And to check that answer: http://www.1728.org/quadratc.htm
Step-by-step explanation:
Tan R = 20/21
tan R = 0.9524
answer is C. 0.9524
