Can the sides of a triangle have lengths of 1, 41, and 45?
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According to the given information, the maximum distance between the satellite and the earth is 510 km.
The function that represents the elliptical route of the satellite is presented as follows;
The compass of the Earth, R = ,370 km.
The equation of an cirque is presented as follows;
a = The major axis( the longer axis), which gives the maximum distance
between the satellite and Earth.
b = The minor axis( the shorter axis)
By comparison, we get;
a² = 47,334,400 km²
Therefore;
a = √(47,334,400 km²) = 6,880 km.
The distance between the satellite and the face of the Earth, d, is given as follows;
d = a - R
Which gives;
d = 6,880 km - 6,370 km = 510 km
Distance between the satellite and the face of the Earth, d = 510 km.
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