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2 years ago

The equation of a parabola in vertex form is y = 2(x - 3)2 + 5. What is the standard form

Mathematics

1 answer:

Alexxx [7]2 years ago

7 0

hello :

y = 2(x + 3)² - 5

y = 2(x²+6x+9) -5

y = 2x² +12x +13...(answer : A) y=2x^2+12x+13 )

Option (a) is correct.

The standard form the equation is

Step-by-step explanation:

Given : the vertex form of the equation of a parabola is

We have to write the given equation in standard form and choose the correct from the given options.

Consider the given equation of parabola

The standard form of equation of parabola is

We can obtain the standard form by expanding the square term in the given equation.

Using algebraic identity , we have,

Solving brackets, we get,

Simplify, we get,

Thus, The standard form the equation is

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oksian1 [2.3K]

Answer:

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Step-by-step explanation:

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3 years ago

triangle ABC is Isosceles CA and CB are equal AB is parallels to the x- axis. Work out the coordinate of A. Given that BC=5cm wo

BabaBlast [244]

Answer:

The perimeter of the triangle ABC is 17 cm.

Step-by-step explanation:

Consider the Isosceles triangle ABC.

The sides CA and CB are equal with measures, 5 cm.

The base angles are assumed to be x° each. Hence, the angle ACB is 2x°.

The altitude CP divides the base AB into two equal halves and the angle ACB is also cut into halves.

Consider the right angled triangle ACP.

The sum of all the angles in a triangle is 180°.

Determine the value of x as follows:

x° + x° + 90° = 180°

2x° = 90°

x° = 45°

Compute the length of side AP as follows:

$cos\ 45^{0}=\frac{AP}{CA}$

$\frac{1}{\sqrt{2}}=\frac{AP}{5}$

$AP =\frac{5}{\sqrt{2}}\\\\AP=3.5$

Then the length of side AB is:

AB = AP + PB

= 3.5 + 3.5

= 7 cm

The perimeter of triangle ABC is:

Perimeter = AB + CA + CB

= 7 + 5 + 5

= 17

Thus, the perimeter of the triangle ABC is 17 cm.

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Step-by-step explanation:

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