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andrew-mc [135]
3 years ago
9

Photo attached. Thanks in advance!

Mathematics
2 answers:
jonny [76]3 years ago
7 0
A zero in front of the x would make this a difference of two perfect squares. All of the other option would interfere by adding another term.
Iteru [2.4K]3 years ago
5 0
HEY THERE !!

CORRECT answer is C. 0

because 0 will produce difference of squares other all will not.

HOPE IT HELPED YOU.
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Write an equation that could be used to solve the given problem: if twice a number is increased by 15 , the result is the same a
Semmy [17]
Equation 2X+15= X-10

X=-25
7 0
3 years ago
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Match the new coordinates that define the figure after dilation with a center at the origin by the given scale factor.
Lemur [1.5K]

Answer:

Step-by-step explanation:

What are the answers you had to do on the test right now

7 0
3 years ago
By what number should 1 1/2 be divided to get 2/3 ? *
andrew-mc [135]

Answer:

1

Step-by-step explanation:

1) The equation is 1 1/2 ÷ x = 2/3

2) You can multiply 2/3 with 1 1/2 to get your answer

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Hope this helps!

4 0
3 years ago
5x + 8 − 3x = −10<br><br> x = −9<br> x = −1<br> x = 1<br> x = 9
zvonat [6]

Answer:

-9

Step-by-step explanation:

7 0
3 years ago
Find the perimeter of the triangle with vertices ​A(negative 2​,2​,3​), ​B(4​,negative 4​,3​), and ​C(7​,6​,4​).
gayaneshka [121]

Answer:

P\approx 28.872\,\text{units}

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}

for the side AB: A(-2,2,3) and B(4,-4,3)

AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}

AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}

AB = \sqrt{72}

for the side BC: B(4,-4,3) and C(7,6,4)

BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}

BC = \sqrt{110}

for the side CA: C(7,6,4) and A(-2,2,3)

CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}

CA = \sqrt{98}

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

P = AB + BC + CA

P = \sqrt{72} + \sqrt{110} + \sqrt{98}

P\approx 28.872\,\text{units}

this is the perimeter of triangle ABC

6 0
3 years ago
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