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MakcuM [25]
2 years ago
14

Hi, help ASAP please.

Mathematics
1 answer:
Kisachek [45]2 years ago
7 0

Answer:

17.3

Step-by-step explanation:

50 - 32.7 = 17.3

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The length of a rectangular garden is 6 more than its width. If the perimeter is 32 feet, what is the width and the area of the
PolarNik [594]

Answer:

{\fbox{ \sf{Width \: of \: a \: rectangular \: garden \:  = 5 \: feet}}}

\boxed{ \sf{ \: Area \: of \: a \: rectangular \: garden = 55 {ft}^{2}}}

Step-by-step explanation:

\star Let the width of a rectangular garden be 'w'

\star Length of a rectangular garden = 6 + w

\star Perimeter of a rectangular garden = 32 feet

<u>\longrightarrow</u><u> </u><u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u> :

\boxed{ \sf{ \: Perimeter \: of \: a \: rectangle \:  =  \: 2(length + width}}

\mapsto{ \text{32 = 2(6 + w + w)}}

\text{Step \: 1 \:  : Collect \: like \: terms}

Like terms are those which have the same base

\mapsto{ \text{32 = 2(6 + 2w) }}

\text{Step \: 2 \:  : Distribute \: 2 \: through \: the \: parentheses}

\mapsto{ \text{32 = 12 + 4w}}

\text{Step \: 3 \:  : Swap \: the \: sides \: of \: the \: equation}

\mapsto{ \text{4w + 12 = 32}}

\text{Step \: 4 \:  : Move \: 12 \: to \: right \: hand \: side \: and \: change \: its \: sign}

\mapsto{ \text{4w = 32 - 12}}

\text{Step \: 5 \:  : Subtract \: 12 \: from \: 32}

\mapsto{ \sf{4w = 20}}

\text{Step \: 6 \:  : Divide \: both \: sides \: by \: 4}

\mapsto{ \sf{ \frac{4w}{4}  =  \frac{20}{4}}}

\text{Step \: 7 \:  : Calculate}

\mapsto{ \text{w = 5}}

Width of a rectangular garden = 5 feet

\longrightarrow <u>Substituting </u><u>/</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>w </u><u>in </u><u>6</u><u> </u><u>+</u><u> </u><u>w </u><u>in </u><u>order </u><u>to </u><u>find</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular </u><u>garden</u>

\mapsto{ \sf{Length = 6 + w = 6 + 5 =  \bold{11 \: feet} }}

\longrightarrow <u>Finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having</u> <u>length of 11 feet and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>feet</u> :

\boxed{ \sf{Area \: of \: a \: rectangle = length \:∗ \:  width}}

\mapsto{ \text{Area \:  =  \: 11 \: ∗ \:   5}}

\mapsto{ \sf{Area \:  = 55 \:  {ft}^{2} }}

Area of a rectangular garden = 55 ft²

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

6 0
3 years ago
What is a fraction for 6:100
Mariulka [41]

Answer:

it's 3/50

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
How do you write negative 4 tenths as a fraction?
jasenka [17]

Answer:

-4/10

Step-by-step explanation:

6 0
3 years ago
The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to th
EleoNora [17]

Answer:

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W  - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

6 0
3 years ago
-20 + 4x = -6x<br> x = 5<br> x = -5<br> x = 2<br> x = -2
Cerrena [4.2K]

Answer:

x=2

Step-by-step explanation:

Hint use m a t h w a y. Its a algebra problem solver.

4 0
2 years ago
Read 2 more answers
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