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tensa zangetsu [6.8K]
3 years ago
12

If 3x-4+8=12+2x then x=?

Mathematics
1 answer:
vova2212 [387]3 years ago
5 0

Answer:

8

Step-by-step explanation:

Combine like terms, -4 and 8, 2x and 3x.

After combining the terms, you get x+4=12.

Subtract 4 from both sides and get x=8

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Will mark brainliest help!
kakasveta [241]

Answer:

52.5

Step-by-step explanation:

Since ED ≈ AD, ∆AED is a isosceles triangle where <EAD and <AED has same angle measurement

Now, m<B = 105°, since ABCD is a parallelogram, <B = <D

so, m<ADC = 105° so, m<ADE = 180°-105° = 75°

Now, m<EAD+m<AED+m<ADE = 180°

or, m<AED+m<AED+m<ADE = 180°

or, x+x+75°=180°

or, 2x=180+75°

or, 2x=105°

or, x=52.5°

3 0
2 years ago
Can someone help me? And possibley tell me how to solve this as well? I'm totally clueless haha
Bumek [7]

Answer:

? = 3

Step-by-step explanation:

To find the value of ?, substitute one of the ordered pairs from the table [except (0, 0)] into the given formula and solve for ?.

Given formula:

\sf y=\boxed{?} \:x

Substitute x = 1 and y = 3 into the formula:

\sf 3=\boxed{?} \:1

To isolate ? divide both sides by 1:

\implies \sf \dfrac{3}{1}=\dfrac{\boxed{?} \:1}{1}

\implies \sf 3=\boxed{?}

Therefore, ? = 3:

\implies \sf y=3x

Check by inputting another value of x from the table into the found formula and comparing the calculated y-value:

\sf x=-2 \implies y=3(-2)=-6 \quad \boxed{\sf correct}

\sf x=3 \implies y=3(3)=9 \quad \boxed{\sf correct}

5 0
2 years ago
Read 2 more answers
if the number 517*324 is completely divisible by 3, then what is the smallest whole number that could replace the *?​
Lelechka [254]

Answer:

2

Step-by-step explanation:

5+1+7+x+3+2+4=x+22

x+22 is divisible by 3,

multiple of 3 are 3,6,9,12,15,18,21,24,27,...

if x=2 ,then x+22=2+22=24

so smallest number is 2

8 0
2 years ago
I put $500 in a saving account that earns 6% interest compounded semi-annually. How much interest will be in the account after 2
Nuetrik [128]
\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$500\\&#10;r=rate\to 6\%\to \frac{6}{100}\to &0.06\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{semi-annually, thus twice}&#10;\end{array}\to &2\\&#10;t=years\to &2&#10;\end{cases}&#10;\\\\\\&#10;A=500\left(1+\frac{0.06}{2}\right)^{2\cdot 2}\implies A=500(1.03)^4\implies A=562.754405

now, "A" is the accumulated amount, including the earned interest, how much interest was it earned?  well, is just A - P.
3 0
3 years ago
Solve for n.<br> -6n = -5 - 5n<br> n=
goblinko [34]

1. Simplify both sides

−6n=−5−5n

−6n=−5+−5n

−6n=−5n−5

2. Add 5n to both sides

−6n+5n=−5n−5+5n

−n=−5

3. Divide both sides by -1.

−n /−1 = −5 /−1

n=5

So the variable n, is equal to 5

4 0
3 years ago
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