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4 years ago

Please help asap! Leaf chart

Mathematics

1 answer:

Eva8 [605]4 years ago

8 0

Answer is B
Each number under the leaf side is the other half of the stem.
Therefore,
1 | 7 =1.7
1 | 3 =1.3
3 | 7 =3.7
So on and so forth.

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What is the value of a?<br><br> 5(a-4)-8a=55? <br> Please help :)

Ad libitum [116K]

If you want to calculate 5*(a-4) - 8*a = 55, you have to do few steps to get to know the value of the a.

5*a - 20 - 8*a = 55
-3*a = 55 + 20
-3*a = 75 /(-3)
a = - 25

The correct result and the value of the a is -25.

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3 years ago

Y=x^2-4x-2 and y=-x-2

erastova [34]

X^2-4x-2=-x-2 so try to get s by itself on one side

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3 years ago

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Using Logarithmic Properties to Solve an Equation<br> plsssss help mee!!!!

saw5 [17]

Answer:

1). x=5

c)x=1

d)x=4

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3 years ago

The scale on a map is 1 in. : 50 mi. The actual distance between the two cities is 350 miles. What is the distance between the c

Luba_88 [7]

The answer is 7 because when you divide 50 from 350 I️t gives you seven.

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4 years ago

To estimate the mean height μ of male students on your campus, you will measure an SRS of students. You know from government dat

denis-greek [22]

Answer:

a) The standard deviation of x must be 0.25 inches.

b) We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

Step-by-step explanation:

The 68-95-99.7 states that:

68% percent of the measures of a normally distributed sample are within 1 standard deviation of the mean.

95% percent of the measures of a normally distributed sample are within 2 standard deviations of the mean.

99.7% percent of the measures of a normally distributed sample are within 3 standard deviations of the mean.

The standard deviation of the population is 2.8. This means that $\sigma = 2.8$ .

(a) What standard deviation must x⎯⎯⎯ have so that 95% of all samples give an x⎯⎯⎯ within one-half inch of μ?

We want to have a sample in which 2 standard deviations are within 0.5 inches of the mean.

So, the standard deviation of the sample must be:

$2s = 0.5$

$s = 0.25$

The standard deviation of x must be 0.25 inches.

(b) How large an SRS do you need to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a)?

We have that the standard deviation of a sample of length n is given by the following formula:

$s = \frac{\sigma}{\sqrt{n}}$ .

We want $s = 0.25$ and we have $\sigma = 2.8$ . So

$0.25 = \frac{2.8}{\sqrt{n}}$

$0.25\sqrt{n} = 2.8$

$\sqrt{n} = 11.2$

$\sqrt{n}^{2} = (11.2)^{2}$

$n = 125.44$

We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

8 0

4 years ago