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2 years ago

13

Really stuck help The picture below is the problem

1 answer:

iren [92.7K]2 years ago

5 0

Answer:

Step-by-step explanation:

figure one

formula length x width x height

plug in 7 x 2 x 3

volume 42 cm^3

figure 2

formula length x width x height

plug in 3 x 2 x 7

volume 42 cm ^3

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Jim needs to move his firewood from his truck to the woodpile in his house. He estimates that he will move 1/8 of the total wood

Dafna1 [17]

1/6 of the wood in one hour. Let me help you with future problems i use this app called socratic it helps alot trust

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3 years ago

e is a math tutor. She charges each student $210 for the first 7 hours of tutoring and $20 for each additional hour. When the nu

dmitriy555 [2]

Part 1 :
if the number of hours (h) is greater than 7.
Equation for the amount(A) in dollar is
Amount (A) = 210 + (h-7)x20

Part 2 :
if she earns 410,
with the same equation
410 = 210 + (h-7)x 20
200 =(h-7)x 20
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3 years ago

What is the inverse of the function f(x) = 4x + 8?

morpeh [17]

Answer:

(A) h(x) = 1/4x -2

Step-by-step explanation:

Given: f(x)=4x+8

Rewrite with y: y=4x+8

Switch x and y: x=4y+8

Solve for y: x-8=4y

(x-8)/4=y

1/4x-2=y

y=1/4x-2

This means that h(x) = 1/4x -2 is the correct answer

8 0

3 years ago

PLZ HELP NO ONE HAS BEEN ABLE TO HELP ME

madam [21]

$6 - 2(x - y) = 3x + 5 \\ 6 - 2x + 2y = 3x + 5 \\6 - 5 = 3x + 2x - 2y \\ 1 = 5x - 2y \\ 5x - 2y = 1$
So; the answer is: A. 5x-2y=1

7 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago