Easy, just divide
kelly=440mi/8hr=220mi/4hr=110mi/2hr=55mi/1hr
alberto=468mi/9hr=156mi/3hr=52mi/1hr
55>52
kelly drove 55mi in 1 hour
55-52=3
she drove 3 miles more in 1 hour
Answer:
decimal: x0.6 or fraction: 2/3
Step-by-step explanation:
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The area of the rectangular pen is 
The cost of material used to make one side is 
The cost of material used to make the other sides is 
Now , the fence to be build around the rectangular pen has four sides, the first opposite sides are equal, let assume each of the to be x yard and the other opposite sides are also equal as well let assume of the to be y yard
So the cost is mathematically represented as

=> 
=> 
Now the area of the fence is mathematically represented as

=> 
=> ![C = 9x + 6[\frac{24}{x} ]](https://tex.z-dn.net/?f=C%20%3D%20%20%209x%20%20%2B%20%206%5B%5Cfrac%7B24%7D%7Bx%7D%20%5D)
=> ![C = 9x + [\frac{144}{x} ]](https://tex.z-dn.net/?f=C%20%3D%20%20%209x%20%20%2B%20%20%5B%5Cfrac%7B144%7D%7Bx%7D%20%5D)
Now differentiating


At minimum 
So




Now substituting for x in the equation above to obtain minimum cost
![C = 9(5.66) + [\frac{144}{5.66} ]](https://tex.z-dn.net/?f=C%20%3D%20%20%209%285.66%29%20%20%2B%20%20%5B%5Cfrac%7B144%7D%7B5.66%7D%20%5D)

Answer:
All three are rational numbers.
Step-by-step explanation:
I used Desmos (a graphing calculator online) and the roots were all able to be written with fractions.
Answer:
0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Mean of 0.6 times a day
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

In which




So

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.