Answer:
3.9 mi/h
Step-by-step explanation:
We assume that the given speeds are the speeds of the boats relative to the water. If c is the speed of the current, we have ...
time = distance/speed
47/(15 +c) = 40/(20 -c)
47(20 -c) = 40(15 +c) . . . . . . multiply by (20-c)(15+c)
940 -600 = 40c +47c . . . . . add 47c-600
340 = 87c . . . . . . . . . . . . . . . simplify; next divide by 87
c = 340/87 ≈ 3.9080 . . . . mi/h
The speed of the current is about 3.9 mi/h.
The answer is B!
I could explain further if needed!
Wait what grade is this in also what class is this
Answer:I think the answer is 5/12.
Step-by-step explanation:
Sorry if I am wrong. :) but it should be correct.
Answer:
Area of Walkway = 12x+16
Step-by-step explanation:
Area of Garden = 4(2.5x + 1.5) <u>[Garden Area]: (10x + 6)</u>
Area of Garden and Walkway = 5.5(4x+4) <u>[Total Area]: (22x + 22)</u>
Area of Walkway = [Total Area] - <u>[</u>Garden Area<u>] </u>
Area of Walkway = [5.5(4x+4)] - <u>[</u>4(2.5x + 1.5)<u>]</u>
Area of Walkway = [22x+22)] - <u>[</u>10x + 6)<u>]</u>
<u>Area of Walkway = 12x+16</u>
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