Answer:
the new side lengths are 10.5 , 9 and 6 inches
the new triangle has the following sides: 5, 4, 3 inches
the perimeter of the first triangle is 36 inches
the perimeter of the second triangle is 12 inches
area of the first triangle is 54 inches squared
area of the second triangle is 6 inches squared
Step-by-step explanation:
<u>first question:</u>
sides are 7,6,4. multiply each one by 3/2 or 1.5
7 x 1.5 = 10.5 or 12/2
6 x 1.5 = 9
4 x 1.5 = 6
the new side lengths are 10.5 , 9 and 6 inches
<u>second question:</u>
multiply each side by 1/3
the sides are 15, 12, 9, so:
15 x 1/3= 5
12 x 1/3 = 4
9 x 1/3 = 3
the new triangle has the following sides: 5, 4, 3
normal sides are 3 and 4
hypotenuse is 5
<u>question a: (calculate perimeter)</u>
<u></u>
<u><em>the perimeter of a triangle</em></u><em>: </em><u><em>you add all the sides</em></u>
the first triangle has 15, 12, 9 for its sides so:
15+12+9 = 36
the perimeter of the first triangle is 36
the second triangle has 5,4,3 for its sides so:
5+4+3 = 12
the perimeter of the second triangle is 12
<u>question b: (calculate the area of both triangles)</u>
area of a triangle: h x b/2: height times base divided by 2
the first triangle has sides, 15,12,9
height is 9 and base is 12, so:
9 x 12/2 = 54 inches squared
area of the first triangle is 54 inches squared
the second triangle has sides, 5,4,3
height is 3 and base is 4, so:
3 x 4/2 = 6 inches squared
area of the second triangle is 6 inches squared
