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3 years ago

5

ramesh took a loan of rs 50000 from urmila at the rate of 10%p.a. if he paid half of the principal and all the interest at the e

nd of 3 years in how many years should he pay the remaining amount with total interest of 20000 from the beginning?

1 answer:

cricket20 [7]3 years ago

7 0

Answer:

Its not ramesh its rameesha

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Help please! I need help with this two step equations

kykrilka [37]

Answer:

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2 years ago

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PLEASE HELP ON ALL QUESTIONS !! <br><br><br><br><br><br><br>THANK YOU TO WHO EVER ANSWERS :)

saveliy_v [14]

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2 years ago

3. A sign company is building a sign with the dimensions shown. What is the area, in square feet, of the sign? Round to the near

Aleks04 [339]

Answer:

84.87sq ft

Step-by-step explanation:

Let ABC be the triangle and AD be the perpendicular on BC such that BD=DC=7ft.

Now, it is known that $\frac{DC}{AC}=cos60^{0}$

$AC=\frac{7}{\frac{1}{2}}$

$AC=7ft$

Now, in triangle ADC, we have

$(AC)^{2}=(AD)^{2}+(DC)^{2}$

$(14)^{2}=(AD)^{2}+(7)^{2}$

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$AD=12.12ft$

Now, area of the triangle= $\frac{1}{2}{\times}b{\times}h$

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= $84.87sq ft$

Thus, area of the building is 84.87sq ft.

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2 years ago

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

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The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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2 years ago

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2 years ago