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ki77a [65]
3 years ago
13

What is 13.50 rounded to the nearest tenth

Mathematics
2 answers:
Mkey [24]3 years ago
7 0

Answer:

13.5

Step-by-step explanation:

13.50 is already rounded to the nearest tenth because the 5 is in the tenth place.

13.50 is basically 13.5

If you're looking for 13.5 rounded to the nearest ones or whole number, the answer would be 14 because any number that is five or greater is rounded up while any number that is four or less is rounded down.

Fed [463]3 years ago
3 0
13.5 is already rounded to the nearest tenth, so the answer is 13.5
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Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
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Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

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