Therefore, the quadratic funtion is: f(x)=0.004x²+0.06x+77.6 x=year of the beginning of the interval - 1980
The life expectancy for females born between 1995 and 2000 is when x=1995-1980=15 Therefore: f(15)=0.004(15)²+0.06(15)+77.6 f(15)=0.004(225)+0.06(15)+77.6 f(15)=79.4
The life expectancy for females born between 2000 and 2005 is when: x=2000-1980=20 therefore: f(20)=0.004(20)²+0.06(20)+77.6 f(20)=1.6+1.2+77.6 f(20)=80.4
Answer: The funtion is: f(x)=0.004x²+0.06x+77.6 x=year of the beginning of the interval - 1980
The life expectancy for females born between 1995 and 2000 is 79.4 years. The life expectancy for females born between 2000 and 2005 is 80.4 years.
<span>Solutions </span> To solve this problem we have to use the quadratic function. An <span>equation where the highest exponent is (usually "x") is a square (2).</span>
28 split into two groups could be 12 : 16. To check the work, see if 3/4 is equal to 12/16. It is, so this is the accurate ratio, as 12 + 16 = 28 and 12/16 = 3:4.
If each pack of trail mixes is targeted to weigh 9.25 oz and must be within 0.23 oz of the target in order to be accepted, then rejected masses x, are those which weighs less than 9.02 oz or greater than 9.48 oz.