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2 years ago

Write equivalent expressions using distributive property. m(4+7)

Mathematics

1 answer:

yulyashka [42]2 years ago

4 0

Hey there!

m(4 + 7)

= 1m(4 + 7)

DISTRIBUTE m WITHIN the PARENTHESES

= m(4) + m(7)

= 4(m) + 7(m)

= 4(1m) + 7(1m)

= 4m + 7m

COMBINE the LIKE TERMS

= 11m

Therefore, your answer is: 11m

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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Write a polynomial function with rational coefficients so that P(x) = 0 has the given roots. 4, 16, and 1 + 9i

bulgar [2K]

I remember dis, yey

so if a polynomial has roots $r_1$ , $r_2$ , $r_3$ , it can be factored into
$f(x)=a(x-r_1)^b(x-r_2)^c(x-r_3)^d$ where a,b,c,d are constants

also, if a polynomial has rational coefients and a+bi is a root, then a-bi must also be a root

so our roots we need are
4,16, 1+9i and 1-9i

so assuming multiplity 1 (that means we have something like [/tex]f(x)=a(x-r_1)^1(x-r_2)^1(x-r_3)^1[/tex])

we get that your function is
$P(x)=(x-4)(x-16)(x-(1+9i))(x-(1-9i))$ which simplifies to
$P(x)=(x-4)(x-16)(x-1-9i)(x-1+9i)$ which expands to
$P(x)=x^4-22x^3+186x^2-1768x+5248$

3 0

4 years ago

What is the answer -50 1/2+(-12.3) pls help

umka21 [38]

Answer:

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7 0

2 years ago

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Please help with this question thanks

ololo11 [35]

the highest fair would be 240 customers charging 11 dollars with a profit of 2,640 dollars

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3 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$

$\mathrm{Cancel\:the\:common\:factor:}\:10^{-12}$

$=\frac{12.6}{35.4\pi \left(10^{-2}\times \:2.5\right)^2}$

$=\frac{12.6}{0.025^2\times \:35.4\pi }$ ∵ $\left(10^{-2}\times \:2.5\right)^2=0.025^2$

$=\frac{12.6}{0.022125\pi }$ ∵ $35.4\pi\times 0.025^2=0.022125\pi$

$=\frac{12.6}{0.06950 }$

F $=181.274$ N

Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.

i.e. F $=181.274$ N

7 0

3 years ago

Find the measure of angle x in the figure below A.35° B.47° C.51° D.62°

Dafna11 [192]

First of all, we know that a line is 180°. This means if we add the angles of 61°, 57°, and angle y, we should get 180°.

$\sf 61\textdegree +57\textdegree+y=180\textdegree$

Simplify:

$\sf 118\textdegree +y=180\textdegree$

Subtract 118° to both sides:

$\sf y=62\textdegree$

We also know that all three angles of a triangle add up to 180°. So we have:

$\sf 67\textdegree+62\textdegree +x=180\textdegree$

Simplify:

$\sf 129\textdegree +x=180\textdegree$

Subtract 129° to both sides:

$\sf x=\boxed{\sf 51\textdegree}$

5 0

3 years ago

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