Question

Is ( 0,0) a solution to this system? y<=x^2-4 y>2x-1?

Answer 1

No.

Your proposed solution does not satisfy the first inequatlity.
  0 ≤ 0 - 4 . . . . . not true

Answer 2

Answer:

The point $(0,0)$ is not a solution of the system of inequalities

Step-by-step explanation:

we have

$y\leq x^{2} -4$ -----> inequality A

$y> 2x-1$ -----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities

then

the ordered pair must be satisfy the inequalities of the system

Verify

For $x=0, y=0$

substitute the value of x and the value of y in the inequalkity A and in the inequality B

Inequality A

$0\leq 0^{2} -4$

$0\leq -4$ -------> is not true

therefore

The point $(0,0)$ is not a solution of the system of inequalities