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Dvinal [7]
3 years ago
5

Which one is higher -33 ft or -92 ft

Mathematics
2 answers:
ahrayia [7]3 years ago
8 0

Answer:

-92

Step-by-step explanation:

because its farther away from 0

kap26 [50]3 years ago
7 0

Answer:

-33

Step-by-step explanation:

0

-33

-92

when working in negatives the closer to 0 the higher the number.

Hope this helps.

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Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
You want to draft a four ­player tennis team. There are eight players to choose from. How many different teams can you form?
Butoxors [25]

We want to make a 4 players team, and there are total 8 players. As we know the order of selection does not matter in a team of players, only the combination of players matters.

So we would use concept of Combinations and It will be choose 4 out of 8 players.

The formula for Combination is given as follows :-

nCr = \frac{n!}{r!*(n-r)!} \\\\
Choose \;4 \;out \;of \;8 \;players \\\\
8C4 = \frac{8!}{4!*(8-4)!} = \frac{8!}{4!*4!} \\\\
8C4 = \frac{8*7*6*5*4*3*2*1}{(4*3*2*1)*(4*3*2*1)} = \frac{8*7*6*5}{4*3*2*1} =\frac{1,680}{24} = 70 \;combinations

Hence, Total number of different teams = 70 combinations.

4 0
3 years ago
Find 26 2/3 % of 90.
Doss [256]

Answer:

I said 24. I hope this helps and works

7 0
3 years ago
The band in a local school was selling bumper stickers to raise money. The net amount A in dollars raised by selling b bumper st
iris [78.8K]

Answer:

  D.  740

Step-by-step explanation:

Put the given value of b into the formula and do the arithmetic:

  A(150) = 5×150 -10 = 750 -10

  A(150) = 740

The band raised $740 from their sales.

7 0
3 years ago
Why is school so stupid???
mestny [16]

Answer:

why is school stupid?today i will tell you bc you have to learn and to work

Step-by-step explanation:

Can you plz give the brain thingy

3 0
3 years ago
Read 2 more answers
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