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2 years ago

PLEASE HELP WHICH STATEMENT IS TRUE

Mathematics

2 answers:

OverLord2011 [107]2 years ago

6 0

Answer:

A. equation A and equation B are both examples of proportional relationships. As they are both linear equations.

Svetradugi [14.3K]2 years ago

3 0

Answer:

The second one is the true statement.

Step-by-step explanation:

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THIS IS VERY IMPORTANT I WILL GIVE BRAINLIEST TO THE PERSON WHO DOES ALL 4 QUESTIONS FOR ME.

devlian [24]

Answer:

6. 130/130.5

7. C, 14 pink roses and 26 red roses

8. A, 18 model cars and 27 model airplanes

9. $359.10

Step-by-step explanation:

Number 6 involves two potential answers because although 30% of 435 is 130.5 you cannot have half of a person at a baseball game.

6 0

3 years ago

Billy Idell is trying to determine how many units of two types of lawn mowers to produce each day. One of these is the Standard

ch4aika [34]

Answer:

Step-by-step explanation:

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6 0

3 years ago

What is 8,000,000 + 100,000 + 7,000 + 400 + 20 + 4 in standard form?

DIA [1.3K]

Answer:

8,107,424

Step-by-step explanation:

The 8,000,000 would stay the same, but the second zero would be switched by a one. The third number would still just be a zero. The other zero would turn into a seven, and the last three numbers would be 4, 2 and 4. You can also find the number by adding.

4 0

3 years ago

Read 2 more answers

Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9

taurus [48]

From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
$\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)$
and
$\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)$

Angle θ is given by
$\theta=180-M-N \\ \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)$

Given that a = 4 units, b = 5 units, and c = 9 units, thus
$\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)$

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
$\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\ \\ -4(x^2+81)+9(x^2-10x+41)=0 \\ \\ -4x^2-324+9x^2-90x+369=0 \\ \\ 5x^2-90x+45=0 \\ \\ x^2-18x+9=0 \\ \\ x=9\pm6 \sqrt{2}$

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
$x=9-6 \sqrt{2}=0.5147$

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.

6 0

4 years ago

1. A = 1/2bh

OleMash [197]

1 and 2 i can't answer without proper data.
3. x+2x+2x+6 = 86
5x+6 = 86
-6 -6
5x = 80
x = 16
Side one: x is 16
Side two: 2x is 2(16) = 32
Side three: 2x+6 is 38

8 0

4 years ago