Maximum area of the rectangle is 
<u>Explanation:</u>
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Considering the dimensions to be in cm
Putting the value of x = 3
Therefore, maximum area of the rectangle is
Complete question :
Leah is creating satin bows for a wedding. From a 15-meter-long ribbon, she first cuts a piece 3 4/9 meters long. Then she cuts a piece 6 5/9 meters long from the remaining ribbon. How much ribbon does Leah have left?
Answer:
5 m
Step-by-step explanation:
Total ribbon cut :
3 4/9 + 6 5/9 =
31/9 + 59/9
= 90 /9
= 10 meters
Total Length of ribbon = 15 m
Ribbon left :
15 - 10 = 5 m
0.30 multiplied by 29 = 8.7 dollars
So first we need to find the area of both using a=3.14*radius*radius
to find the radius we need to divide 35 by 2 (large) and 30 by 2 (medium)
lets do the large first since the raidus is 17.5 we put it into a=3.14*17.5*17.5
and then we get 961.63, for the medium we do a=3.14*15*15 which is 706.50
now for the large 961.63 * 2 is 1923.26 and the price is 19.99
for the medium we do 706.50 * 3 which is 2119.5 and costs 24.99
So the medium pizzas are a better deal
If we're talking about a box with dimensions 10 ft, 19 ft and 20 ft, it's probable that the instructions say to calculate the volume. That would be
V = (10 ft)(19 ft)(20 ft) = 3800 cubic feet.
