The maximum or minimum point of a parabola is called the __________.
1 answer:
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Answer:
y=6^x+0.612 - 4
Step-by-step explanation:
x = -4 ---> horizontal asymptote
m = 6 ---> use points (0, -1) and (1, 5)
Parent function of the graph:
Our equation:
Add alterations:
- Reflections = N/A
- Vertical & horizontal shifts = down 4
- Vertical & horizontal stretches = left approx 0.612
Final equation: y=6^x+0.612 - 4
Answer:
<u>y = -2x + 7</u>
Explanation:
<em><u>y = mx + b</u></em>
<em><u /></em>
<em>m = slope</em>
<em>b = y-intercept</em>
<em>y = a given y coordinate</em>
<em>x = a corresponding x coordinate</em>
<em />
First, we need to find the slope (m).
1) (4, -1)
2) (2/3)
m = slope = =
=
= -2
plug in the values to the equation <u>y = mx + b</u>
<u />
-1 = -2(4) + b
-1 = -8 + b
7 = b
now, we can substitute in m and b into the equation y = mx + b
<u><em>y = -2x + 7</em></u>