Help me pleeeeeeeeeeeeeez

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

c)

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

3 years ago

A rectangular table top has dimensions as 1.52m and 0.75m. Find the perimeter in cm

Elis [28]

That is a question about perimeter of rectangle.

The perimeter of a geometric shape is the sum of the value of the all sides.

In a rectangle, the opposite sides are cogruentes (equals). For example, look at picture below. In that rectangle, the sides AB and DC are equals, and the sides AD and BC are equals.

So, the sides of that rectangular table are: 1.52m, 1.52m, 0.75m and 0.75.

Therefore, the perimeter of that rectangle is $1.52+1.52+0.75+0.75= 4.54$ m.

But that is not the final answer because that is the perimeter in meters and the question want the answer in centimeters.

1 meter has 100 centimeter, so we need to multiplicate the perimeter by 100.

Thus, the perimeter of that rectangular table is $4.54\cdot 100 = 454$ cm.

3 0

3 years ago

I need help getting the answer for the 1st question

Karo-lina-s [1.5K]

If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:

base 1 /height 1=base 2 /height 2

Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
x=8 m²/0.2 m
x=40 m

Answer. the heigth of the tower will 40 m

3 0

3 years ago

a man invested a total of $3,000 in two investments. he made a profit of 3% on the first investment and 4% on the second investm

klio [65]

Let the first investment be x
and second be 3000-x

so 3%of x + 4% of (3000-x) = 107
By solving x = 1300

First investment is 1300
second investment is 1700

7 0

4 years ago

Four students were discussing how to find the unit rate for a proportional relationship. Which method is valid?

LenKa [72]

Answer:

D

Step-by-step explanation:

7 0

3 years ago

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