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KengaRu [80]
2 years ago
6

The width of a rectangle is 4n-8.5 feet and the length is 8.5n+9 feet. Find the perimeter of the rectangle

Mathematics
2 answers:
Eva8 [605]2 years ago
7 0

Answer: P = 25n + 35

Step-by-step explanation:

The perimeter of a rectangle is twice the sum of length and width.

P = 2(l +w)

P = 2((8.5n+9) + (4n +8.5))

P = 2(12.5n +17.5)

P = 25n + 35

Mumz [18]2 years ago
3 0

Answer:

8.5n+9+4n-8.5+8.5n+9+4n-8.5

take the like terms together:

8.5n+4n+8.5n+4n=25n

9-8.5+9

=9.5

final answer=25n+9.5

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<u>Step-by-step explanation:</u>

The formula for compounded annually is: A = P(1 + r)ⁿ   where

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A = 750(1 + 0.04)ⁿ

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8 0
3 years ago
Which rational number does not have a reciprocal
Dmitriy789 [7]

Answer:

the rational numbers that doesn’t have a reciprocal are [math]0 [/math] (which can also be expressed as [math]\frac {0} {x}, x \neq 0 [/math] ), and any number of the form [math]\frac {x} {0} [/math].

Step-by-step explanation:

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Find the recipricol of -b/3
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Step-by-step explanation:

7 0
2 years ago
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
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