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2 years ago

6

The population of deer in a national forest has been increasing by about 5.8% annually. The current population is about 2,200 de

er. The function y = 2,200 - can be used to find the number of deer, y, after x years. What value belongs in the box?

1 answer:

arsen [322]2 years ago

8 0

Answer:

127 goes in the box

Step-by-step explanation:

I hope this helps you.

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The composite figure is made up of a rectangular prism and a___a0___.a1

zavuch27 [327]

Answer:

The composite figure is made up of a rectangular prism and square pyramid

Step-by-step explanation:

The figure on top is square pyramid since the base is a square and the 4 sides are triangles. The bottom is a rectangular prism since the figure is made up of side rectangular faces

8 0

3 years ago

What is the variable of p and k explain please

scoundrel [369]

For the P=-4
what you do is subtracting 6 to the 38 you will have -8p=32 then you will divide-8 to both sides and your answer will be p=-4
check 6-8(-4)=38
6+32=38
38=38

i got K=5.6
what you do is add 13 to the 15 and you will have 28=5k then you will divide 5 to both sides and you will have k=5.6
check 15=5(5.6)-13
15=28-13
15=15

3 0

3 years ago

One line segment is 5 emmore than 4 times the

ollegr [7]

Let the length of the 1st line segment = x

then the length of the second line segment = 4x + 5

The difference in their lengths = 35

so 4x + 5 - x = 35 ... [longer - shorter = 35]

3x = 30

x = 10

so the shorter (1st) line segment is 10 cm long

and the longer (2nd) line segment is 4 * 10 + 5 = 45 cm long

7 0

3 years ago

Subtract express each diffrence in simplest form : 2 - 1/3-9/10 and 4-5/6- 3/8

ivolga24 [154]

The first one is 23/30 and the second one is 2 19/24

3 0

2 years ago

The rate at which the temperature is dropping is 6t 5t2 degrees Celsius per hour t hours after sundown. How much had the tempera

Whitepunk [10]

Using a differential equation, it is found that the temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

<h3>What is the differential equation that describes the temperature in t hours after sundown?</h3>

The rate at which the temperature is dropping is $6t + 5t^2$ degrees Celsius per hour t hours after sundown, hence the <em>differential equation</em> is:

$\frac{dT}{dt} = 6t + 5t^2$

Applying <em>separation of variables</em>, we find the solution as follows:

$\frac{dT}{dt} = 6t + 5t^2$

$dT = (6t + 5t^2) dt$

$\int dT = \int (6t + 5t^2) dt$

$T(t) = \frac{5t^3}{3} + 3t^2 + T(0)$

In which T(0) is the temperature at sundown.

In 3 hours, the change will be of:

$C = T(3) - T(0) = \frac{5t^3}{3} + 3t^2|_{t = 3}$

Hence:

$\frac{5(3)^3}{3} + 3(3)^2 = 45 + 27 = 72$

The temperature dropped 72 degrees Celsius between sundown and 3 hours after sundown.

You can learn more about differential equations at brainly.com/question/24348029

5 0

2 years ago