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2 years ago

Plot the x- and y-intercepts of function f(x)=x

2 answers:

8 0

This is the basic equation.
There is no shifts, because you don’t see any addition signs.

So, the x and y intercepts are at the origins (0,0).

Hope this helps!

katrin2010 [14]2 years ago

5 0

Because f(x)=x, goes through origin. So x and y -intercept are one point (0,0).

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A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago

What is the value of the expression 2/4^-3?

Kisachek [45]

$\frac{2}{4^-3} \\ \\ \frac{2}{ \frac{1}{4^3} } \\ \\ \frac{2}{ \frac{1}{64} } \\ \\ 2 \times 64 \\ \\ 128 \\ \\ Answer: \fbox {128}$

5 0

3 years ago

Sushil was thinking of a number. Sushil divides by 7 then adds 7 to get an answer of 12. Form an equation

VikaD [51]

Answer:

The number is 35.

35 divided by 7 is 5, and 5 plus 7 is 12.

3 0

2 years ago

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-2(3y - 6) + 4(5y - 8) = 92

Whitepunk [10]

Answer:

y = 8

Step-by-step explanation:

$-2(3y - 6) + 4(5y - 8) = 92\\\\\mathrm{Expand\:}-2\left(3y-6\right)+4\left(5y-8\right):\quad 14y-20\\14y-20=92\\\\\mathrm{Add\:}20\mathrm{\:to\:both\:sides}\\14y-20+20=92+20\\\\Simplify\\14y=112\\\\\mathrm{Divide\:both\:sides\:by\:}14\\\frac{14y}{14}=\frac{112}{14}\\\\Simplify\\y= 8$

3 0

2 years ago

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A package states that there are 60 calories in 12 crackers and 75 calories in 15 crackers. Since the relationship is proportiona

Masteriza [31]

Answer:

900 calories

Step-by-step explanation:

each cracker has 5 calories so you would times 5 by 180 which gets you 900

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2 years ago

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