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DanielleElmas [232]
2 years ago
7

BIG IDEAS MATH

Mathematics
1 answer:
IgorC [24]2 years ago
7 0

Answer:

106

Step-by-step explanation:

See attached

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The radius of a circle is 3 cm what is the circumference
malfutka [58]

the circumference is about 18.85

6 0
3 years ago
What is the equation of y = x ^ 3 with the given transformations? vertical compression by a factor of horizontal shift 8 units t
dexar [7]

Answer: y = 3 (x -4)^3

Step-by-step explanation: horizontal shift of 4 units to the right (subtract 4 units from the x):   y = 3(x - 4)^3

Vertical shift 3 units down (subtract 3 units from the function):   y = 3(x - 4)^3 - 3

5 0
3 years ago
If a = 7 - 4√3, find the value of a + 1/a​
irga5000 [103]

Answer:

Step-by-step explanation:

To calculate a+1/a, we first need to calculate for a.

a = 7 - 4 * \sqrt[2]{3}

square root of 3 = 1.73

a = 7 - 4 * 1.73

a = 7 - 6.9

a = 0.1

0.1 + 1 / 0.1 = 0.1 + 10 = 10.1

Now, in case 4 wasn't being multiplied with the square root of 3, and instead, it was four root of 3, I am gonna do the calculations again:

a = 7 - \sqrt[4]{3}

a = 7 - 1.31

a = 5.69

5.69 + 1 / 5.69 = 5.69 + 0.17 = 5.86

Hope I Helped!

5 0
2 years ago
A circle is centered at the point (-7, -1) and passes through the point (8, 7).
Sergeu [11.5K]

we know the circle's center is at -7, -1, and we know the circle itself passes through 8,7, the distance from the center to a point on it is by definition its radius, therefore

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\\stackrel{center}{(\stackrel{x_1}{-7}~,~\stackrel{y_1}{-1})}\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[8-(-7)]^2+[7-(-1)]^2}\implies r=\sqrt{(8+7)^2+(7+1)^2}\\\\\\r=\sqrt{15^2+8^2}\implies  r=\sqrt{225+64}\implies \boxed{r=17}

and since we know that x = -15 for such a point, then

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2\qquad center~~(\stackrel{-7}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{17}{ r}\\\\\\\[x-(-7)]^2+[y-(-1)]^2=17^2\implies (x+7)^2+(y+1)^2=289\\\\\\\stackrel{\textit{since we know x = -15}}{(-15+7)^2+(y+1)^2=289}\implies (-8)^2+\stackrel{FOIL}{(y^2+2y+1^2)}=289\\\\\\64+y^2+2y+1=289\implies y^2+2y=224\implies y^2+2y-224=0\\\\\\(y+16)(y-14)=0\implies y=\begin{cases}-16\\14\end{cases}

since it's a circle, it touches x = -15 twice, check the picture below.

6 0
2 years ago
Lines a and b are parallel.<br><br><br><br> What is the measure of angle m
kvasek [131]
55 degrees because a line measures 180 degrees so you subtract 125 from 180
6 0
2 years ago
Read 2 more answers
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