Question

The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?

Answer 1

Answer:

Smallest integer is " 3 "

Step-by-step explanation:

Integers are

          3 , 4 , 5 , 6  

 3 + 4 + 5 + 6 = 18

Answer 2

Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

$\sf \: x + x + 1 + x + 2 + x + 3 = 18$

$\sf \: 4x + 1 + 2 + 3 = 18$

$\sf4x + 6 = 18$

$\sf4x = 18 - 6$

$\sf4x = 12$

$\boxed{ \mathfrak{x = 3}}$

Now,

• 1st number = x = 3
• 2nd number = x+1 = 3+1 = 4
• 3rd number = x+2 = 3+2 = 5
• 4th number = x+3 = 3+3 = 6

The four numbers are 3,4,5,6 respectively and the smallest number among them is 3...~