Answer:
-2=9
0=-5
1=-3
2=-1
5=5
Step-by-step explanation:
Replace 'x' with the number corresponding to the side of the table.
Ex. f(-2)=2(-2)-5
Quadrilateral ABCD is a kite
AB is congruent to AD -- definition of a kite
BC is congruent to DC -- definition of a kite
draw a line segment AC
AC is congruent to itself -- identity
triangle ABC is congruent to triangle ADC -- SSS
angle ABC is congruent to ADC
QED
The dimensions of a box that have the minium surface area for a given Volume is such that it is a cube. This is the three dimensions are equal:
V = x*y*z , x=y=z => V = x^3, that will let you solve for x,
x = ∛(V) = ∛(250cm^3) = 6.30 cm.
Answer: 6.30 cm * 6.30cm * 6.30cm. This is a cube of side 6.30cm.
The demonstration of that the shape the minimize the volume of a box is cubic (all the dimensions equal) corresponds to a higher level (multivariable calculus).
I guess it is not the intention of the problem that you prove or even know how to prove it (unless you are taking an advanced course).
Nevertheless, the way to do it is starting by stating the equations for surface and apply two variable derivation to optimize (minimize) the surface.
You do not need to follow with next part if you do not need to understand how to show that the cube is the shape that minimize the surface.
If you call x, y, z the three dimensions, the surface is:
S = 2xy + 2xz + 2yz (two faces xy, two faces xz and two faces yz).
Now use the Volumen formula to eliminate one variable, let's say z:
V = x*y*z => z = V /(x*y)
=> S = 2xy + 2x [V/(xy)[ + 2y[V/(xy)] = 2xy + 2V/y + 2V/x
Now find dS, which needs the use of partial derivatives. It drives to:
dS = [2y - 2V/(x^2)] dx + [2x - 2V/(y^2) ] dy = 0
By the properties of the total diferentiation you have that:
2y - 2V/(x^2) = 0 and 2x - 2V/(y^2) = 0
2y - 2V/(x^2) = 0 => V = y*x^2
2x - 2V/(y^2) = 0 => V = x*y^2
=> y*x^2 = x*y^2 => y*x^2 - x*y^2 = xy (x - y) = 0 => x = y
Now that you have shown that x = y.
You can rewrite the equation for S and derive it again:
S = 2xy + 2V/y + 2V/x, x = y => S = 2x^2 + 2V/x + 2V/x = 2x^2 + 4V/x
Now find S'
S' = 4x - 4V/(x^2) = 0 => V/(x^2) = x => V =x^3.
Which is the proof that the box is cubic.
This means that we have to didvide the 12 inches wide side into 3 parts: one of 3.5 inches, and two other, of equal size (the margins).
the margins together will have (12-3.5=8,5) inches, which means that each of them will hace half of this: so we have to divide 8.5 into 2.
this is: :
8.5/2=4.25
so he has to to put it 4.25 inches from each side.
Answer:
You should first make sure you explain what exactly is the question, before delete others answers.♀️♀️
Step-by-step explanation: