Answer:
The dimensions of the yard are W=20ft and L=40ft.
Step-by-step explanation:
Let be:
W: width of the yard.
L:length.
Now, we can write the equation of that relates length and width:
(Equation #1)
The area of the yard can be expressed as (using equation #1 into #2):
(Equation #2)
Since the Area of the yard is
, then equation #2 turns into:
![800=W*(5W-60)](https://tex.z-dn.net/?f=800%3DW%2A%285W-60%29)
Now, we rearrange this equation:
![800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0](https://tex.z-dn.net/?f=800%3DW%2A%285W-60%29%2F%2F800%3D5W%5E2-60W%2F%2F5W%5E2-60W-800%3D0)
We can divide the equation by 5 :
![W^2-12W-160=0](https://tex.z-dn.net/?f=W%5E2-12W-160%3D0)
We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since
and
. The equation factorised looks like this:
![(W-20)(W+8)=0](https://tex.z-dn.net/?f=%28W-20%29%28W%2B8%29%3D0)
Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:
![5*20-60=40](https://tex.z-dn.net/?f=5%2A20-60%3D40)
Therefore, the dimensions of the yard are W=20ft and L=40ft.
Answer: -6
Step-by-step explanation: It changed -6 each round because -6x3=-18.\
Hope this helped!
Turn it into transcript, It's upside down and I can't see it properly.
Answer:
u need to put a picture so we know what your talking about
Correct answer is
A) -4(m+y)