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snow_tiger [21]
2 years ago
12

Solve for x: 1/6(6x+12)+5x>26

Mathematics
2 answers:
seropon [69]2 years ago
7 0
From this we can simplify to get x>4

Stells [14]2 years ago
3 0

Answer:

5+7800¶¶wyy

upuewwryieosv

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Please help fast!!!! Find the seventh term of the geometric sequence if a1=7 and r=3
statuscvo [17]

Answer:

15309 Im pretty sure

Step-by-step explanation:

a7=ar^7

=7(3^7)

7 x 2187=15309

6 0
3 years ago
Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.
nataly862011 [7]

Answer:

Step-by-step explanation:

x = small barrettes

y = large barrettes

13x + 11y = 142.......multiply by -1

13x + 12y = 149

-----------------------

-13x - 11y = -142 (result of multiplying by -1)

13x + 12y = 149

------------------------add

y = 7..........large barrettes used 7 yards

13x + 11y = 142

13x + 11(7) = 142

13x + 77 = 142

13x = 142 - 77

13x = 65

x = 65/13

x = 5........small barrettes used 5 yards

4 0
3 years ago
Find the area of the following triangle. Show each of the math steps that you use to find the area. Then explain how to go about
Aleksandr [31]

Right angled triangle

  • Base=B=2.4cm
  • Height=H=1.8cm

Area:-

\\ \rm\rightarrowtail \dfrac{1}{2}BH

\\ \rm\rightarrowtail \dfrac{1}{2}(2.4)(1.8)

\\ \rm\rightarrowtail 1.2(1.8)

\\ \rm\rightarrowtail 2.16cm^2

4 0
2 years ago
Justin bought 5 apples and 4 oranges for £45. On another occasion, he bought 2 apples and 8 oranges which cost £50. Find the cos
Vitek1552 [10]

Answer:

the cost of 3 apples and 7 oranges be £15 and £35 respectively

Step-by-step explanation:

Let us assume the apple be x

And, the oranges be y

Now according to the question

5x + 4y = £45

And,

2x + 8y = £50

Multiply by 2 in equation 1

So,

10x + 8y = £90

2x + 8y = £50

8x = £40

x = £5

And, y be

5(£5) + 4y = £45

£25 + 4y = £45

4y = 20

y = £5

So, the cost of 3 apples and 7 oranges be £15 and £35 respectively

5 0
3 years ago
Multiply and simplify. Question is in the picture.
frez [133]
The answer should be b¹². You add the exponents of each constant. In the case of the simple b the exponent would be one.
5 0
3 years ago
Read 2 more answers
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