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guapka [62]
3 years ago
8

What additional piece of information must be known in order to calculate the volume of the cylinder below?

Mathematics
2 answers:
kicyunya [14]3 years ago
8 0

Answer:

The correct answer is -

2. the height of the cylinder  

Step-by-step explanation:

The volume of the cylinder is given as :

V= \pi r^{2} h

In the given figure, we have the radius. So, we need the height in order to calculate the volume.

So, the correct answer is -

2. the height of the cylinder  

djyliett [7]3 years ago
5 0

For this case we have that by definition, the volume of a cylinder is given by:

V = \pi * r ^ 2 * h

Where:

r: It is the radius of the cylinder

h: It is the height of the cylinder

We have as data, observing the figure, that they give us the radio. Then, the height is missing.

Answer:

Option B

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20% of off $75 is $60.
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2w + y = 6<br> a. Find y if w = -4<br> b. Find y if w = 10
krok68 [10]
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a bag contains eleven counters. five are white. a counter is taken out the bag and is not replaced. a second counter is taken ou
Fed [463]

Answer:

\displaystyle P(A)=\frac{6}{11}

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

\Omega=\{WW,WN,NW,NN\}

We are required to compute the probability that only one of the counters is white. It means that the favorable options are

A=\{WN,NW\}

Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is

\displaystyle \frac{5}{11}

Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now

\displaystyle \frac{6}{10}

Thus the option WN has the probability

\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}

Now for the second option NW. The initial probability to pick a non-white counter is

\displaystyle \frac{6}{11}

The probability to pick a white counter is

\displaystyle \frac{5}{10}

Thus the option NW has the probability

\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}

The total probability of event A is the sum of both

\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}

\boxed{\displaystyle P(A)=\frac{6}{11}}

7 0
3 years ago
Suppose demand d for a company's product at cost x is predicted by the
11111nata11111 [884]

Answer:

0.36x ² + 815.04x + 11,340

Step-by-step explanation:

Revenue = price × quantity

p(x) = x+14

d(x) = 0.36x + 810

Revenue = price × quantity

= (x + 14) * (0.36x + 810)

= 0.36x² + 810x + 5.04x + 11,340

= 0.36x ² + 815.04x + 11,340

Company's revenue = 0.36x ² + 815.04x + 11,340

3 0
3 years ago
A box contains 35 gems, of which 10 are real diamonds and 25 are fake diamonds. Gems are randomly taken out of the box, one at a
Sonja [21]

Answer:

Step-by-step explanation:

The total number of ways of selecting 3 gems of any kind without replacement is 35 * 34 * 33 = 39270

Now selecting 2 gems from 25 is 25C2

25 C 2 = 25 * 24/2 = 300

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Total selection = 300 * 10 = 3000

P(gems) = 3000 / 39270

P(gems) = 300/3927

P(gems) = 100/1309

6 0
3 years ago
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