It's not actually 20 pts it's 10 pts if you send a question and you want 20 pts off it would be 10 for other ppl. like
10pts off = 5
20pts off = 10
30pts off = 15
and so on so it's like counting by 5's each time you lose points
Answer:
A. E(x) = 1/n×n(n+1)/2
B. E(x²) = 1/n
Step-by-step explanation:
The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as
P(x) = {1/n, x = 1,2...n}
Therefore,
Expectation of X
E(x) = summation {xP(×)}
= summation {X×1/n}
= 1/n summation{x}
= 1/n×n(n+1)/2
= n+1/2
Thus, E(x) = 1/n×n(n+1)/2
Value of E(x²)
E(x²) = summation {x²P(×)}
= summation{x²×1/n}
= 1/n
Answer:
Given the function: y=f(x) = 3x+2
when x=-2 at the beginning of the interval [-2, 5],
then;
y = 3x+2 begins at
y= 3(-2)+2 = -6+2= -4.
and
when x=5 at the end of the interval [-2, 5],
y = 3x+2 ends up at
y= 3(5)+2 = 15+2= 17.
So,
y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21
and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7
So, the average rate of change of y with respect to x over the interval
[-2, 5] is given by ;
=
Therefore, the average rate of change y with respect to x over the interval is, 3
Step-by-step explanation:
x=25,y=15 Not to sure abt this answer but I think I got it
Answer:
For f(x) = 2x + 3 and g(x) = -x 2 + 1, find the composite function defined by (f o g)(x)
(f o g)(x) = f(g(x))
= 2 (g(x)) + 3
= 2( -x 2 + 1 ) + 3
= - 2 x 2 + 5 Given f(2) = 3, g(3) = 2, f(3) = 4 and g(2) = 5, evaluate (f o g)(3)
Step-by-step explanation:
