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2 years ago

Plz help I can’t figure this out

Mathematics

2 answers:

Yuki888 [10]2 years ago

8 0

Answer:

The answer is 57.

Step-by-step explanation:

${\tt{\underline{\underline{\pink{SOLUTION:}}}}}$

To solve the above equation we will follow the BODMAS rule.

$\blue\star$ BODMAS is an order of mathematic operations.
$\blue\star$ BODMAS rule is to be followed while solving expressions in mathematics.

It stands for :

$\purple\star$ B = bracket
$\purple\star$ O = order of power
$\purple\star$ D = division
$\purple\star$ M = multiplication
$\purple\star$ A = addition
$\purple\star$ S = subtraction

Solving this question by bodmas rule :

$\begin{gathered}\qquad{\sf{ = 9 + 6( {2}^{2} + 4)}}\\\\\qquad{\sf{ = 9 + 6(2 \times 2 + 4)}}\\\\\qquad{\sf{ = 9 + 6(4 + 4)}}\\\\\qquad{\sf{ = 9 + 6(8)}}\\\\\qquad{\sf{ = 9 + 6 \times 8}}\\\\\qquad{\sf{ = 9 + 48}}\\\\\qquad{\sf{ = 57}}\end{gathered}$

Hence, the answer is 57.

$\rule{300}{2.5}$

Julli [10]2 years ago

6 0

Answer:

Step-by-step explanation:

$9+6 (2^2 +4)\\9+6 (4 +4)\\9+6 *8\\9+48\\57$

Your answer is 57.

Hope this helps! Brainliest would be much appreciated! Have a great day! :)

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ivolga24 [154]

Answer:

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(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

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(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

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