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love history [14]
3 years ago
9

help! The steps to prove the Law of Sines with reference to ∆ABC are given. Arrange the steps in the correct order.

Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Answer:

The correct order is given below

Step-by-step explanation:

1). Draw a perpendicular from point A to side BC. Let AD = h

2). sin A = h/c and sin C = h/a

3). h = c Sin A, h = a sin C

4). c Sin A =a sin C

5). Divide both side by Sin A * Sin C

6). c Sin A/(Sin A * Sin C) =a sin C/(Sin A * Sin C)

7). c/sin C = a/Sin A

8). Similarly prove that,  c/sin C = b/Sin B

9).  c/sin C =  b/Sin B = a/Sin A

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A box of popcorn weighs 15/16 pounds. The box contains 1/3 buttered popcorn and 2/3 cheesy popcorn. How much does the cheesy pop
ella [17]

we know that

To find the weight of the cheesy popcorn Multiply the total weight by the proportion of the cheesy popcorn

so

\frac{15}{16} *\frac{2}{3}=\frac{30}{48}=\frac{5}{8}\ pounds

therefore

<u>the answer is</u>

the weight of the cheesy popcorn is \frac{5}{8}\ pounds

4 0
3 years ago
Read 2 more answers
If y = 3x squared + 4 find the value of y when x = 2
qaws [65]

Answer:

The value of y is 16.

Step-by-step explanation:

You have to substitute x = 2 into the equation :

y =  {3x}^{2}  + 4

Let x = 2,

y = 3( {2)}^{2}  + 4

y = 3(4) + 4

y = 12 + 4

y = 16

8 0
4 years ago
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HELP!!! THE FIRST ANSWER GETS MARKED AS THE BRAINLIEST
inna [77]

Answer: oops sorry

Step-by-step explanation:

4 0
3 years ago
How do you figure out #9 and #10
Ann [662]
#9 the sum of two angles is 90 degrees, creating a right angle.

#10 the sum of the two angles is 180 because the form a supplementary angle
4 0
4 years ago
A bucket that weighs 4lband a rope of negligible weight are used todraw water from a well that is 80ftdeep. The bucket is filled
liq [111]

Answer:

Workdone = 3200 lb.ft

Step-by-step explanation:

We are told that the bucket is filled with 40 lb of water but water leaks out of a hole in the bucket at a rate of 0.2lb/s

Thus,

Weight of water at any given time (t) would be;

w(t) = 40 - 0.2t - - - - (1)

We are told the bucket is pulled up at a rate of 2ft/s.

Thus, height at time (t); y = 0 + 2t = 2t

Since y = 2t,

Then,t = y/2

Put y/2 for t in eq 1

Thus; w(y) = 40 - 0.2(y/2)

w(y) = 40 - 0.1y

Now, at y = 80 ft, we have;

w(80) = 40 - 0.1(80)

w(80) = 40 - 8 = 32 lb

Since 32 lbs are left, it means there is always water in the bucket.

Thus, work done is;

W = 80,0[∫(Total weight).dy]

W = 80,0[∫[(weight of rope) + (weight of bucket) + (weight of water)]dy]

W = 80,0[∫[0 + 4 + 40 - 0.1y]dy]

Integrating, we have;

W = [44y - y²/20] at boundary of 80 and 0

So,

W = [44(80) - 80²/20] - [0 - 0²/20]

W = 3200 lb.ft

8 0
3 years ago
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