The price of the car after 10 years is $7524.25 if the new car costs $34,000 and its value depreciates at 14% of its value each year.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let y represent the value of the car after x years. A new car costs $34,000 and its value depreciates at 14% of its value each year. Hence:
y = 34000(0.86)ˣ
After 10 years:
y = 34000(0.86)¹⁰ = 7524.25
The price of the car after 10 years is $7524.25 if the new car costs $34,000 and its value depreciates at 14% of its value each year.
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Answer:
<u><em>(-2, 6)</em></u>
Step-by-step explanation:
<em>10x + 10y = 40 -(1)</em>
<em>5x + 3y = 8 -(2)</em>
<em></em>
<em>(1) => 10x + 10y = 40</em>
<em>(2) x 2 => 10x + 6y = 16</em>
<em>=> 4y = 24</em>
<em>=> y = 6</em>
<em></em>
<em>5x + 3(6) = 8</em>
<em>5x = -10</em>
<em>x = -2</em>
<em></em>
<em>Solution = (-2, 6)</em>
Answer: 4.98
Step-by-step explanation:fractions are dividing so if j=25 and k=5 the division problem would be 25 divided by 5 then u would subtract 0.02 to get 4.98
Answer:
√(4/5)
Step-by-step explanation:
First, let's use reflection property to find tan θ.
tan(-θ) = 1/2
-tan θ = 1/2
tan θ = -1/2
Since tan θ < 0 and sec θ > 0, θ must be in the fourth quadrant.
Now let's look at the problem we need to solve:
sin(5π/2 + θ)
Use angle sum formula:
sin(5π/2) cos θ + sin θ cos(5π/2)
Sine and cosine have periods of 2π, so:
sin(π/2) cos θ + sin θ cos(π/2)
Evaluate:
(1) cos θ + sin θ (0)
cos θ
We need to write this in terms of tan θ. We can use Pythagorean identity:
1 + tan² θ = sec² θ
1 + tan² θ = (1 / cos θ)²
±√(1 + tan² θ) = 1 / cos θ
cos θ = ±1 / √(1 + tan² θ)
Plugging in:
cos θ = ±1 / √(1 + (-1/2)²)
cos θ = ±1 / √(1 + 1/4)
cos θ = ±1 / √(5/4)
cos θ = ±√(4/5)
Since θ is in the fourth quadrant, cos θ > 0. So:
cos θ = √(4/5)
Or, written in proper form:
cos θ = (2√5) / 5
Answer:
The answer is exponential and constant multiplicative rate of change
Step-by-step explanation:
i took it and got it right
