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2 years ago

9

Which is the equation for the nth term of the geometric sequence: -4,8,-16...?

1 answer:

kobusy [5.1K]2 years ago

6 0

Answer:

aₙ=(-2)ⁿ*2.

Step-by-step explanation:

1) -4*(-2)=8; 8*(-2)=-16; -16*(-2)=32, ...

2) the required equation is:

aₙ=(-1)ⁿ*2ⁿ*2; ⇒ aₙ=(-2)ⁿ*2 or aₙ=(-1)ⁿ*2ⁿ⁺¹.

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The correct answer would be $204.80 because if she keeps doubling whats in the bank the amount after the $ .20 then it would be doubled to $ .40 and so on

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3 years ago

When a gas changes into a liquid, it is called ____________, and the speed of the molecules is ___________. A. condensation; inc

saul85 [17]

Answer:

condensation, decreases trust me is right

Step-by-step explanation:

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago

The scale in the drawing is 2 cm : 5 m. Select from the drop down the correct numbers into the boxes to give the length, width,

Gelneren [198K]

The length, width, and area will be 25m, 15m, and 375m².

<h3>How to calculate the area?</h3>

From the information given, the scale in the drawing is 2cm : 5m and the length and width are given as 10cm and 6cm respectively.

Length = 10cm = 10 × 2.5 = 25m

Width = 6cm = 6 × 2.5m = 15m

Area = Length × Width

Area = 25 × 15

Area = 375m²

Therefore, the area is 375m².

Learn more about area on:

brainly.com/question/25292087

#SPJ1

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2 years ago

What’s the central angle??

arsen [322]

The answer is GOJ

The central angle would be the O which is the center, and that would be in the middle of the other two letters.

8 0

3 years ago

Read 2 more answers