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2 years ago

How do you graph 3x= -135

Mathematics

2 answers:

statuscvo [17]2 years ago

7 0

Answer:

You would graph a vertical line at (-49, 0)

Step-by-step explanation:

3x = -135

Divide both sides by 3

x = -45

You would graph a vertical line at (-49, 0)

P.S., that system acts strange sometimes so be sure to only do one square up once you press -45. :)

myrzilka [38]2 years ago

3 0

Answer:

see below

Step-by-step explanation:

first isolate x

3x = -135

divide both sides by 3

3x/3 = x

-135/3 = -45

x = -45

we can then graph it

x is gonna be equal to -45

so draw a point on the x intercept at -45 and draw a vertical line going up and down

it should look like the graph shown below

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Solve the system <br> 2x+2y+z=-2 <br> -x-2y+2z=-5<br> 2x+4y+z=0

drek231 [11]

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

Step-by-step explanation:

The given is,

$2x+2y+z=- 2$ .......................................(1)

$-x-2y+2z=-5$ ......................................(2)

$2x+4y+z=0$ .........................................(3)

Step:1

Equation (2) is multiplied by -1 ( Eqn(2) × -1 )

$x+2y-2z=5$ .............................(4)

Subtract the equation (1) and (4)

$2x+2y+z=- 2$

$x+2y-2z=5$

( - )

$(2x-x)+(2y-2y)+(z+2z)=(-2-5)$

$x+3z=-7$ ......................(5)

Step:2

Equation (2) is multiplied by -2 ( Eqn(2) × -2)

$2x+4y-4z=10$ ........................(6)

Subtract equation (6) and (3),

$2x+4y-4z=10$

$2x+4y+z=0$

( - )

$(2x-2x)+(4y-4y)+(-4z-z)= (10-0)$

$-5z=10$

$z = - \frac{10}{5}$

z = -2

From the equation (5),

$x+3z=-7$

$x+(3)(-2)=-7$

$x = -7+6$

x = -1

From equation (1),

$2x+2y+z=- 2$

Substitute x and z values,

$(2)(-1)+2y+(-2)=-2$

$2y - 4=2$

$2y=4-2$

$2y=2$

$y=\frac{2}{2}$

y = 1

Step:3

Check for solution,

$-x-2y+2z=-5$

Substitute x,y and z values,

$-(-1)-(2)(1)+(2)(-2)=-5$

$1-2-4=-5$

-5 = -5

Result:

The values of (x,y,z) are (3,-1,-2) , if the given are equations $2x+2y+z=- 2$ , $-x-2y+2z=-5$ and $2x+4y+z=0$ .

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3 years ago

Please, please help with this question!! I don't understand it!

Kazeer [188]

Answer:

Step-by-step explanation:

Find the area of each shape, then multiply by 20, then round to nearest hundred.

Half circle:

=πr²/2

=50π

=157.08

Large square:

=L•w

=20(22)

=440

Small square:

=L(w)

=12(3)

=36

Triangle:

=b(h)/2

=8(3)/2

=12

Btu req:

=(157.08+440+36+12)(20)

=(645.08)(20)

=12901.6

=12900 BTU

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3 years ago

What is the solution to the system of equations below?

ANEK [815]

A. x = 7, y = 4, z = 3

How?

Just plug in the numbers.

7 + 4 + 3 = 14

11 + 3 = 14

14 = 14

Next.

4 + 3 = 7

Next.

3 = 3

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3 years ago

Find the distance between (2,4) and (12, 9) on a coordinate plane. round to the nearest tenth if necessary. *

atroni [7]

Use pythagoras

d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
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The nearest tenth is 11.2, so the distance is near to 11.2

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(a2·a3·(a−1))2. What is the answer

lora16 [44]

Answer: Assuming the a2 is a with an exponent of 2 and a3 is a with an exponent of 3, the answer is 2a^6-2a^5

Step-by-step explanation: the number after the ^ means to the power of

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