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mixer [17]
3 years ago
7

The center of mass of a triangular solid is at its what?

Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
I believe it is vertex
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Latanya was asked to determine if (375,4) lies on the circle with radius 7 centered at (0.-2). what is her error?
Vilka [71]

The point (3/5,4) would lie on the circle if it makes the equation of the circle to be true

Latansha's equation of the circle is wrong

<h3>How to determine her error?</h3>

The given parameters are:

Center = (a,b) = (0,-2)

Radius, r = 7

The equation of a circle is:

(x - a)^2 + (y - b)^2 = 0

This gives

(x - 0)^2 + (y + 2)^2 = 0

Rewrite as:

x^2 + (y + 2)^2 = 0

In Latanya's first step, we have:

x^2 + (y - 2)^2 = 0

By comparing her first step with x^2 + (y + 2)^2 = 0, we can see that her equation is wrong

Hence, Latansha's error is that she determine the equation of the circle, wrongly.

Read more about circle equations at:

brainly.com/question/1559324

6 0
2 years ago
Solve for x: 3 + 5x = 4x - 6
solniwko [45]

Answer:

3 + 5x = 4x - 6

Let's do it quickly and simply,

Let's gather the like terms

5x - 4x = -6 - 3

x = - 9

Hope it helps!

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!! I WILL RATE BRAINLIEST TO THE FASTEST AND CORRECT ANSWER!!!
Andrej [43]
Not easy:

- 4 < x^4 + 4x^2 ---> 0 < x^4+4x^2+4 = (x^2+2)^2, so it is always positive. Always satisfied. Curious ...

Now the other one:

x^4+4x^2<21 --> x^4+4x^2-21 < 0 --> (x^2+2)^2 - 25 < 0

(x^2+2)^2<25 ->>> x^2+2 < 5 ---> x^2 <3,

So -sqrt(3)<x<sqrt(3) is the answer! Brainliest?
5 0
3 years ago
1 to the tenth power
dmitriy555 [2]
Answer: 1

Explanation:

1 to any power will always be 1
8 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP AND NO VIRS!
Kay [80]

Answer:

C) 84

Step-by-step explanation:

6 0
3 years ago
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