B is the right thing 15 squints
Answer:
WE HAVE FIND HOW MUCH MAY TIME BIGGER IS THE VOLUME OF PYRAMID B THAN PYRAMID A.
The answer is 32 times
Step-by-step explanation:
Volume of Pyramid B = 3136 in³
Volume of Pyramid A = ?
We have to find volume of Pyramid A. As Pyramid is a square pyramid, its volume is given as:
where b = base = 7 and h = height = 6. Substitute the values:
Volume of Pyramid A = 98 in³
To find how many time B is bigger than A, divide volume of B by A:
So, volume of Pyramid B is 32 times bigger than volume of Pyramid A
Answer:
The end behavior of f(x)=2/3x-2 is: as x->+ infinity, f(x)->+ infinity
as x->- infinity, f(x)->- infinity
Step-by-step explanation:
When you are asked about the end behavior of a function, look to see where the function is traveling on the graph. For instance, this graph is linear, so you should look to see if the slope is positive or negative. This linear function is positive, so as x is reaching positive infinity the f(x) would also be reaching positive infinity. As x is reaching negative infinity, f(x) would also be reaching negative infinity. The end behavior of a function describes the trend of the graph on the left and right side of the x- axis. (As x approaches negative infinity and as x approaches positive infinity).
Answer:
x > - 5
x < 10
Step-by-step explanation:
Divide 7x>-35 by 7
Divide - 5x>-50 by - 5
Since we divide by a negative whe change the inequality sign.
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
