Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?
To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).
Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.
Translations and dilations (along with reflections and rotations) belong to a group known as transformations.
Answer:
$5.5
Step-by-step explanation:
6 * N (notebook) + 3 * P (pen) = 27
n = 1.5 +P
6 * (1.5 + P) + 3 * P = 27
9 +6p +3p = 27
9p = 18
p (pen): $2
N (notebook): $3.5
combined cost of 1 pen and 1 notebook: $2 + $ 3.5 = $ 5.5
Answer:
Her final answer should have been x = 1/2.
Step-by-step explanation:
Her 2 errors were that she didn't distribute the 2x to both 4 and -17 and that she made the 13 positive instead of negative when she added 4 and -17 together.
Correct solution:
8(x-3)+7=2x(4-17)
8x-24+7=8x-34x
-17=-34x
The negatives on both sides cancel each other out
x = 1/2
For area A, the width will be √(3A/4), so for the three rugs, the widths are 6 ft, 9 ft, 12 ft. Corresponding lengths are 4/3 times that, so are 8 ft, 12 ft, 16 ft.
The rug dimensions are
.. 6 ft x 8 ft
.. 9 ft x 12 ft
.. 12 ft x 16 ft
Pick the one(s) that are on your list.
QUESTION 1: In these type of question, the easiest way to get the answer is try to plug in the x and y values from the options given in the equation given, So in the first question all the choice except C are more then 14 if you plug in x and y's, for eg, if you plug in x = 3 and y = 2 , you get (3+3)2 = 14 6 x 2 = 14 12 is not equal to 14, so this eliminates this choice but if you chose C you get, (11+3)1 = 14 14 = 14 so this makes C the solution for first question and for the second question do the same thing, and the answer will be D. Hope this helps
QUESTION 2: 5xy + 9 = 44
5xy = 35
xy = 7
solution pairs are:
C. (1, 7) and (7, 1)
not mentioned: (-1.-7) and (-7, -1)
Hope this helps
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