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3 years ago

A coin is flipped 4 times. what is the probability of the coin landing on tails all 4 times

Mathematics

2 answers:

DaniilM [7]3 years ago

6 0

Half the chance of landing tail once(1/2)

Half the chance of land tails four times (1/2 of 1/2 of 1/2 of 1/2)

1/16

tankabanditka [31]3 years ago

3 0

the probablity of the coin landing on tails all four times is

1/4

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Fill in the other coordinate for the line 7x - 5y = 21: (4, )

garri49 [273]

7x - 5y = 21....(4,?)...so sub in 4 for x and solve for y
7(4) - 5y = 21
28 - 5y = 21
-5y = 21 - 28
-5y = - 7
y = 7/5

check..
7(4) - 5(7/5) = 21
28 - 35/5 = 21
28 - 7 = 21
21 = 21 (correct)

the other coordinate is 7/5......(4,7/5)

8 0

3 years ago

It's from the chapter : "exponents and powers"<br>i need the workings too<br>please help

labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

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3 years ago

Stacy thinks her employer may not be withholding the correct amount from her paychecks for state income tax. She made arrangemen

Degger [83]

the answer is

Stacy’s employer is withholding too little for state income tax.

tbh main idk how to do it but i found it on quizLIT so you know main. hope u pass it king

https://quizlet.com/169654356/financial-literacy-tax-basics-flash-cards/

8 0

3 years ago

Read 2 more answers

A doctor studies the known cancer patients in a certain town. The probability that a randomly chosen resident has cancer is foun

Alex777 [14]

Let the event 'has cancer' be C, and the event 'works for Ajax' be A.
P(C) = 0.0019. P(A) = 0.28
The events A and C are independent if P(C|A) = P(C).
P(C|A) = 0.0019 = P(C).
Therefore the answer is YES.

4 0

3 years ago

Zara has forgotten her 4-digit PIN code. She knows the first digit is a prime number and the 4 digits make a number divisible by

vredina [299]

Answer:

2,500 different sets

Step-by-step explanation:

According to the scenario, calculation of the given data are as follows,

Let 4-digit PIN code be WXYZ

As first digit is a prime number

So, W = 1, 2, 3, 5, 7

n(W) = 5

X and Y are number from 0 - 9

So, n(X) = 10 & n(Y) = 10

Z makes the whole number divisible by 2.

So, Z must even number

So, Z = 0,2,4,6,8 or n(Z) = 5

We can calculate the number of different sets by using following formula,

n(W) × n(X) × n(Y) × n(Z)

By putting the value, we get

5 × 10 × 10 × 5 = 2,500

6 0

3 years ago