We have the following statements and results.
A. A rhombus is a quadrilateral.
True. A rhombus is a quadrilateral all of which sides have the same length.
B. A quadrilateral is a polygon with four angles.
True. A polygon is a plane figure with at least three straight sides and angles, and typically five or more.
C. In quadrilateral PQRS, ∠P and ∠S are opposite angles.
False. If we have a quadrilateral PQRS, that means that ∠P and ∠S are consecutive angles, not opposite.
D. The diagonals of a rhombus are perpendicular and bisect each other.
True. It is true that the diagonals of a rhombus are always perpendicular and bisect each other.
Answer.
Statement C is false.
Answer:
- top: no solution
- bottom: x = 7
Step-by-step explanation:
I find a graphing calculator very helpful to solving radical equations. It helps avoid extraneous solutions.
<u>top</u>
√(-14x +2) = x -3
-14x +2 = x² -6x +9 . . . . . square both sides
x² +8x +7 = 0 . . . . . . . . . .subtract the left side
Descartes' rule of signs tells you this has no positive real solutions. (There are no sign changes among the coefficients.) The value of the radical will be non-negative, so we must have x-3≥0, or x≥3. Since there are no positive real solutions to the quadratic, there are no values of x≥3 that will satisfy the equation. NO SOLUTION
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<u>bottom</u>
4√(x -3) = 8 . . . . . given
√(x -3) = 2 . . . . . . divide by 4
x -3 = 4 . . . . . . . . . square both sides
x = 7 . . . . . . . . . . . add 3
Answer:
the product of 1.54 and 2.6 is 4.004. I think
Answer:
everywhere except between 2 and 5
(between -inf and 2 and between 5 and inf)
Step-by-step explanation:
pls brainlist