180 degrees of the triage
From question,
lacy learned 34 recipes in 17 weeks,
so in 1 week she learns = 34/17 =2 recipes,
hence she learns 40 recipes in
= 40*2
=80 recipes.
<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span><span>1/2</span><span>(<span><span>2g</span>−3</span>)</span></span>=<span>−<span>4<span>(<span>g+1</span>)</span></span></span></span>
<span><span>g+<span><span>−3/</span>2</span></span>=<span><span>−<span>4g</span></span>−4</span></span>
<span><span><span>g+<span><span>−3/</span>2</span></span>+<span>4g</span></span>=<span><span><span>−<span>4g</span></span>−4</span>+<span>4g</span></span></span><span><span><span>5g</span>+<span><span>−3</span>2</span></span>=<span>−4</span></span>
5g+−3/2+3/2=−4+3/2
<span><span>
5g</span>=<span><span>−5/</span>2</span></span>
<span><span><span>5g/</span>5</span>=<span><span><span>−5</span>2</span>5</span></span><span>
g=<span><span>−1</span><span>2
Hoped I helped!</span></span></span>
Answer:
8 months
Step-by-step explanation:
194-3m = 217-6m
3m = 23
m=7.666666..... (8 months
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
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