I think it is C. 8 is the greatest it can be, so y can't be more than 8. I'm not 100% sure
Answer:
1 x
f(x)= ------- x4 +c
in(4)
Step-by-step explanation:
lol it was had to put it one here but I tried my best.
Let a and o represent the numbers of apples and oranges sold the first week.
a + o = 108
Then the number sold the second week is
5a +3o = 452
Subtract 3 times the first equation from the second.
(5a +3o) -3(a +o) = (452) -3(108)
2a = 128 . . . . . . collect terms
a = 64 . . . . . . . . divide by 2
o = 108 - 64 = 44 . . . use the first equation to find o
64 apples and 44 oranges were sold the first week.
if the distance from R to S is only half then the other half is S to T. The distance between R and S is (5,2). that should give you the answer
The length of AC is 16 km.
Solution:
Given data:
AB = c = 14 km, ∠A = 30° and ∠B = 89°
AC = b = ?
<u>Let us first find angle C:</u>
<em>Sum of all angles in a triangle = 180°</em>
m∠A+ m∠B + m∠C = 180°
30° + 89° + m∠C = 180°
119° + m∠C = 180°
Subtract 119° from both sides, we get
m∠C = 61°
<u>To find the length of AC:</u>
<em>Using sine formula:</em>
![$\frac{b}{\sin B } =\frac{c}{\sin C}](https://tex.z-dn.net/?f=%24%5Cfrac%7Bb%7D%7B%5Csin%20B%20%7D%20%3D%5Cfrac%7Bc%7D%7B%5Csin%20C%7D)
Substitute the given values in the formula.
![$\frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ }](https://tex.z-dn.net/?f=%24%5Cfrac%7Bb%7D%7B%5Csin%2089%5E%5Ccirc%20%7D%20%3D%5Cfrac%7B14%7D%7B%5Csin%2061%5E%5Ccirc%20%7D)
Multiply by sin 89° on both sides.
![$\sin 89^\circ \times \frac{b}{\sin 89^\circ } =\frac{14}{\sin 61^\circ } \times \sin 89^\circ](https://tex.z-dn.net/?f=%24%5Csin%2089%5E%5Ccirc%20%5Ctimes%20%5Cfrac%7Bb%7D%7B%5Csin%2089%5E%5Ccirc%20%7D%20%3D%5Cfrac%7B14%7D%7B%5Csin%2061%5E%5Ccirc%20%7D%20%5Ctimes%20%5Csin%2089%5E%5Ccirc)
![$b=\frac{14}{0.8746 } \times0.9998](https://tex.z-dn.net/?f=%24b%3D%5Cfrac%7B14%7D%7B0.8746%20%7D%20%5Ctimes0.9998)
![b=16](https://tex.z-dn.net/?f=b%3D16)
The length of AC is 16 km.