Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Step-by-step explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Answer:
33 3/12
Step-by-step explanation:
i’m pretty sure this is right :)
Yes because the line is curved
Your answer here would be letter A because for each year it is multiplied by 5 and so year 6 was 31,250 and 31,250 * 5 is 156,250
Have A Good Day :)
1/7 (x - 3) = 5/7
1/7x - 3/7 = 5/7
1/7x - 3/7 + 3/7 = 5/7 + 3/7
1/7x = 8/7
1/7x(7) = 8/7(7)
X = 56/7
X = 8
